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WITCHER [35]
3 years ago
10

What is 263826 times 28​

Mathematics
2 answers:
UNO [17]3 years ago
8 0

Answer:

7,387,128

Step-by-step explanation:

monitta3 years ago
5 0

Answer:  Your Answer Is 7387128 (:

Step-by-step explanation:  263826 x 28 = 7387128 Hope this helped! (:

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Ollie Drank 3/4 of a 16 oz bottle of juice. How many oz of juice is left in the bottle?
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3/4th of the bottle of juice would be splitting up the 16 oz bottle into 4th, so 16 divided by 4 equals 4. Then because he only drank 3/4th of the bottle multiply the 4 by 3 equaling 12. Then subtract 12 from 16 and you get a total of 4 oz left!!!
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What is the area of the circle shown below? 14 cm​
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Answer:

154cm squared

Step-by-step explanation:

7 0
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NEED HELP PLEASE IM BEGGING YOU PLEASE!!!!!!!!!!!
astra-53 [7]
20. 3 notebooks
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The slope of the line passing through the points (0, 0) and (2, 3) is
MArishka [77]
You can use the equation to find the slope of a line given two points. This equation is y2 - y1 divided by x2 minus x1. The y2 is represented by the y coordinate of the second ordered pair, but it really doesn't matter, either way you get the same answer. The same way the x2 is represented by the x coordinate of the second ordered pair. For this problem, I will just use the normal coordinates. So the second y coordinate is 3. 3 -0 = 3. So your numerator is 3. The second x coordinate is 2. 2-0 = 2. So the denominator is 2. This is 3/2. So your slope would be 3/2. Hope this helps. :D Let me know if you didn't understand something in my explanation.
4 0
3 years ago
Evaluate the indicated limit algebraically. Change the form of the function where necessary. Please write clearly with descripti
alukav5142 [94]

Answer:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3

Step-by-step explanation:

We want to evaluate the limit:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}

To do so, we can divide everything by <em>x</em>². So:

=\displaystyle \lim_{x\to \infty}\frac{3+4.5/x^2}{1-1.5/x^2}

Now, we can apply direct substitution:

\Rightarrow \displaystyle \frac{3+4.5/(\infty)^2}{1-1.5/(\infty)^2}

Any constant value over infinity tends towards 0. Therefore:

\displaystyle =\frac{3+0}{1+0}=\frac{3}{1}=3

Hence:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3

Alternatively, we can simply consider the biggest term of the numerator and the denominator. The term with the strongest influence in the numerator is 3<em>x</em>²<em>, </em>and in the denominator it is <em>x</em>². So:

\displaystyle \Rightarrow \lim_{x\to\infty}\frac{3x^2}{x^2}

Simplify:

\displaystyle =\lim_{x\to\infty}3=3

The limit of a constant is simply the constant.

We acquire the same answer.

6 0
3 years ago
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