A line has a slope of 1 and passes through the point (8, 10). What is its equation in

Ishaan is 222 times as old as Christopher. 353535 years ago, Ishaan was 777 times as old as Christopher.

klemol [59]

<h3><u>Question:</u></h3>

Ishaan is 2 times as old as Christopher. 35 years ago, Ishaan was 7 times as old as Christopher. How old is Christoper now?

<h3><u>Answer:</u></h3>

The present age of Christoper is 42 years old

<h3><u>Solution:</u></h3>

Given that Ishaan is 2 times as old as Christoper

Let the present age of Christoper be "x"

Then, Present age of Ishaan = 2 times as old as Christoper

present age of Ishaan = 2x

<em><u>35 years ago, Ishaan was 7 times as old as Christopher</u></em>

Age of Ishaan 35 years ago = Present age of Ishaan - 35

Age of Ishaan 35 years ago = 2x - 35

Similarly,

Age of christoper 35 years ago = Present age of christoper - 35

Age of christoper 35 years ago = x - 35

From given statement, 35 years ago, Ishaan was 7 times as old as Christopher

Age of Ishaan 35 years ago = 7 times the age of Christoper 35 years ago

(2x - 35) = 7(x - 35)

<em><u>Solve the above equation for "x"</u></em>

2x - 35 = 7x - 245

2x - 7x = -245 + 35

-5x = -210

Thus present age of Christoper is 42 years old

5 0

3 years ago

I don't know how to do this

vesna_86 [32]

He could have 30 dimes and 13 quartars

7 0

3 years ago

I need help ! <br> <img src="https://tex.z-dn.net/?f=3%5Csqrt%7B5%7D%20%2B5%5Csqrt%7B15%7D" id="TexFormula1" title="3\sqrt{5} +5

Feliz [49]

Answer:

26

Step-by-step explanation:

SORRY IF IM WRONG

6 0

2 years ago

Match each expression written in standard form to the equivalent expression in factored form

den301095 [7]

Answer:

1. 15x^7y^2 + 4x^3 => x^3(15x^4y^2 + 4)

2. 15x^7y^2 + 3x => 3x(5x^6y^2 + 1)

3. 15x^7y^2 + 6xy => 3xy(5x^6y + 2)

4. 15x^7 + 10y^2 => 5(3x^7 + 2y^2)

Step-by-step explanation:

To obtain the answer to the question, first let us factorise each expression. This is illustrated below:

1. 15x^7y^2 + 4x^3

Common factor is x^3, therefore the expression is written as:

x^3(15x^4y^2 + 4)

2. 15x^7y^2 + 3x

Common factor is 3x, therefore the expression is written as:

3x(5x^6y^2 + 1)

3. 15x^7y^2 + 6xy

Common factor is 3xy, therefore the expression is written as:

3xy(5x^6y + 2)

4. 15x^7 + 10y^2

Common factor is 5, therefore the expression can be written as:

5(3x^7 + 2y^2)

4 0

3 years ago

= 118

oee [108]

Answer:

number of $20 bill = 4

Number of $5 bill = 5

Step-by-step explanation:

Given that:

Total number of $5 and $20 bills = 9

Let :

Number of $5 bills = x

Number of $20 bills = y

Combined worth of all bills = $105

x + y = 9 - - - (1)

5x + 20y = 105 - - - (2)

From (1)

x = 9 - y

Substitute x = 9 - y into (2)

5(9 - y) + 20y = 105

45 - 5y + 20y = 105

15y = 105 - 45

15y = 60

y = 60/15

y = 4

x = 9 - y

x = 9 - 4 = 5

Hence,

number of $20 bill = 4

Number of $5 bill = 5

6 0

3 years ago