Question: Given that BE bisects ∠CEA, which statements must be true? Select THREE options.
(See attachment below for the figure)
m∠CEA = 90°
m∠CEF = m∠CEA + m∠BEF
m∠CEB = 2(m∠CEA)
∠CEF is a straight angle.
∠AEF is a right angle.
Answer:
m∠CEA = 90°
∠CEF is a straight angle.
∠AEF is a right angle
Step-by-step explanation:
Line AE is perpendicular to line CF, which is a straight line. This creates two right angles, <CEA and <AEF.
Angle on a straight line = 180°. Therefore, m<CEA + m<AEF = m<CEF. Each right angle measures 90°.
Thus, the three statements that must be TRUE are:
m∠CEA = 90°
∠CEF is a straight angle.
∠AEF is a right angle
4,000×0.035×2=280
.................
Answer:
or
Step-by-step explanation:
The expression 
can be simplified by first writing the fraction under one single radical instead of two.
5/15 simplifies because both share the same factor 5.
It becomes 
This can simplify further by breaking apart the radical.
A radical cannot be left in the denominator, so rationalize it by multiplying by √3 to numerator and denominator.
I is a graph equation
It is asking you which of those options will make a line that would cross the two points that are listed in the question
So I am pretty sure the answer is option B
If this answer is not understandable please message me or leave a comment
