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3 years ago

Answer for number 1?

Mathematics

1 answer:

Rufina [12.5K]3 years ago

8 0

Answer:

you need to draw a triangle on the grid

Step-by-step explanation:

find point -3 then 7

then find points -2 and 1

then -5 and 2

then join the points together

hope that helps

pls mark brainliest

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A certain drug concentration of 2.145 mg per 1.716 mL, how many mL are needed to give 2.937 gram of the drug.

Ivenika [448]

Answer:

2,349.6‬ ml

Step-by-step explanation:

To start solving this, i realized that there was a difference in the units given and the units asked for in the answer, so I converted 2.937 grams to 2,397 mg. It is given that there are 2.145 mg of the drug in 1.716 mL, so set up the equation 2.145 / 1.716 = 2,937 / x, where x is the mL of the drug needed. Cross multiply to get 5039.892 = 2.145 x. Divide by 2.145 and get 2,349.6‬ ml

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3 years ago

Which equation has the same solutions as the equation given below?

Lapatulllka [165]

Answer:

Step-by-step explanation:

Also solved eveything

(x+9)^2=49

x^2+18x+81=49

x^2+18x+32=0

a=1, b=18 and c=32

x= (-18 +/- Sqrt (18^2-4×32))/2

x= (-18 +/- Sqrt (324-128))/2

x= (-18 +/- Sqrt (196))/2

x= (-18 +/- 14)/2

x= (-18 +14)/2 = -4/2 =-2

x= (-18 -14)/2 = -32/2 =-16

3 0

3 years ago

Read 2 more answers

|8m| = 104 absolute value

DENIUS [597]

Answer:

m=13

Step-by-step explanation:

l8ml=104

8m=104

⁻⁻⁻ ⁻⁻⁻

8 8

m=13

6 0

3 years ago

Priya said, “It takes more cubes with edge length ⅖ inch than cubes with edge length ⅕ inch to pack the prism.” Do you agree wit

Lyrx [107]

V=A times B times C that is the eqatuion

6 0

3 years ago

Solve the rational function of (check image) and check for extraneous solutions

Oxana [17]

Answer:

Option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

Step-by-step explanation:

Given the expression

$\frac{5}{x}=\frac{4x+1}{x^2}$

Solving the rational function

$\frac{5}{x}=\frac{4x+1}{x^2}$

Apply fraction across multiply: if $\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5x^2=x\left(4x+1\right)$

Subtract x(4x+1) from both sides

$5x^2-x\left(4x+1\right)=x\left(4x+1\right)-x\left(4x+1\right)$

Simplify

$5x^2-x\left(4x+1\right)=0$

5x² - 4x² - x = 0

x² - x = 0

Factor x² - x = x(x-1)

x(x-1) = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

$x=0\quad \mathrm{or}\quad \:x-1=0$

Thus, the solution to the equation is:

$x=0,\:x=1$

But, it is clear that if we substitute x = 0, the equation becomes undefined because we can not have the denominator to be 0.

In other words, the equation is undefined for x = 0

Thus, x = 0 is an extraneous solutions.

Therefore, option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

5 0

3 years ago