A 35.0-g piece of copper wire is heated, and the temperature of the wire changes from 29.0°C to 76.0C. The amount of heat absorb
1 answer:
Answer:
0.15cal/g°C
Explanation:
Given parameters:
Mass of copper piece = 35g
Initial temperature = 29°C
Final temperature = 76°C
Amount of heat absorbed = 243cal
Unknown:
Specific heat of copper = ?
Solution:
The specific heat is the amount of heat supplied to a unit mass of substance that causes a 1°C rise in temperature.
Specific heat C, =
where H is the amount of heat supplied
m is the mass of the copper
T is the temperature
Input the parameters;
C = = 0.15cal/g°C
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Answer:
strongest oxidizing agent:
weakest oxidizing agent:
strongest reducing agent: Y
weakest reducing agent: X
will oxidize Z
Explanation:
The higher the reduction potential of a species, higher will be the tendency to consume electrons from another species. Hence higher will be the oxidizing power of it's oxidized form and lower will be the reducing power of it's reduced form.
Alternatively, higher reduction potential value suggests that the oxidized form of the species acts as a stronger oxidizing agent and the reduced form of the species acts as a weaker reducing agent.
Order of reduction potential:
So, strongest oxidizing agent:
weakest oxidizing agent:
strongest reducing agent: Y
weakest reducing agent: X
As reduction potential of the half cell is higher than the reduction potential of the half cell
therefore
will oxidize Z into
and itself gets converted into X.