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alex41 [277]
3 years ago
12

Please answer! Tap on the photo❤️

Chemistry
1 answer:
lina2011 [118]3 years ago
6 0

Answer:

E

Explanation:

no of grams in picture c = A+B

= 200+10 =210

for D its also 210 ..... the water already contains the salt .....so the mass of salt has added to the mass of water which is still 210

that's all .... have fun

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The diagram below represents a sodium atom bonding to a chlorine atom to form sodium chlorine.
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Sodium Chloride is a compound.
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500ml of a buffer solution contains 0.050 mol nahso3 and 0.031
nydimaria [60]

Answer:

The answers are explained below

Explanation:

a)

Given: concentration of salt/base = 0.031

concentration of acid = 0.050

we have

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b)

we have HSO₃⁻ + OH⁻ ------> SO₃²⁻ + H₂O

Moles i............0.05...................0.01.................0.031.....................0

Moles r...........-0.01.................-0.01................0.01........................0.01

moles f...........0.04....................0....................0.041.....................0.01

c)

we will use the first equation but substituting concentration of base as 0.031 + 10ml = 0.031 + 0.010 = 0.041

Hence, we have

PH = PK a + log[salt]/[acid] = 1.8 + log(0.041/0.050) = 1.71

d)

pOH = -log (0.01/0.510) = 1.71

pH = 14 - 1.71 = 12.29

e)

Because the buffer solution (NaHSO3-Na2SO3) can regulate pH changes. when a buffer is added to water, the first change that occurs is that the water pH becomes constant. Thus, acids or bases (alkali = bases) Additional may not have any effect on the water, as this always will stabilize immediately.

4 0
4 years ago
A solution is made by mixing equal masses of methanol, CH 4 O , CH4O, and ethanol, C 2 H 6 O . C2H6O. Determine the mole fractio
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Answer: The mole fraction of methanol

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The mole fraction of ethanol

Xeth = 0.41

Explanation:

Mole fraction of a component can be determined by:

Xi = moles of i / total moles of the components the components

Where i indicates the component

An equal mass of 100.0g is assumed for both methanol and ethanol

Molar mass of Methanol (CH4O)

= (1*12) + (4*1) +(1*16) =32g/mol

Mole of Methanol = mass of methanol /molar mass of methanol

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Molar mass of ethanol ( C2H6O)

= (2*12)+(6*1)+(1*16) = 46.0g/mol

Mole of ethanol = 100/46

= 2.17mol.

Mole fraction of methanol (Xmeth)

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Mole fraction of ethanol (Xeth)

= moles of ethanol /total moles

= 2.17/((3.13+2.17)

Xeth= 0.41

5 0
3 years ago
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