An atom has 27 protons and 22 neutrons. What is the chemical symbol for the atom?

Sulfuryl chloride is in equilibrium with sulfur dioxide and chlorine gas: so2cl2(g) so2(g) + cl2(g) a system with a volume of 1.

Bess [88]

Answer:

Sulfuryl chloride decreases by -1/21 (-4.76%) (option c)

Explanation:

Denoting

sc= so2cl2(g)

s=so2(g)

c=cl2(g)

Assuming that the compression is an isothermal process , then reaction equilibrium constant in terms of pressure does not change

Kp= psc/ps*pc =

where p= partial pressures

Assuming ideal behaviour , then from Dalton's law,

Xsc₁=psc₁/P₁= psc₁/P₁ = 1 bar/(1 bar + 0.1 bar + 0.1 bar) = 5/6

Xs=ps₁/P₁ = 0.1/1.2=1/12

Xc=pc₁/P₁ = 0.1/1.2=1/12

since Xs=Xc → the reaction started as pure Sulfuryl chloride . Then representing ξ as the extent of reaction and n as the moles

nsc=nsc₀*(1-ξsc) , ns=nsc₀*ξsc , nc=nsc₀*ξsc → n=nsc +ns +nc = nsc₀*(1+ξsc)

therefore

Xs₁=ns₁/n₁=ξsc₁/(1+ξsc₁) → Xs₁*ξsc₁+Xs₁=ξsc₁ → ξsc₁=Xs₁/(1-Xs₁) = (1/12)/(11/12)= 1/11

then from the ideal gas law

ps₁*V₁=ns₁*R*T

after the reduction

ps₂V₂=ns₂*R*T

dividing both equations

(ps₂/ps₁)*(V₂/V₁)=(ns₂/ns₁)=nsc₀*ξsc₂/(nsc₀*ξsc₁) = ξsc₂/ξsc₁

ps₂ = ps₁ * (V₁/V₂) * (ξsc₂/ξsc₁)

since

psc₁*V₁=nsc₁*R*T , psc₂V₂=nsc₂*R*T → psc₂ = psc₁ * (V₁/V₂) * (1-ξsc₂)/(1-ξsc₁)

also knowing that

Kp= psc₁/ps₁² = psc₂/ps₂²

psc₂/ps₂² = psc₁/ps₁² * (V₁/V₂) * (1-ξsc₂)/(1-ξsc₁) / [(V₁/V₂) * (ξsc₂/ξsc₁) ]² =

1 = (V₂/V₁)(1-ξsc₂)*ξsc₁/ [(1-ξsc₁)*ξsc₂]

replacing ξsc₁= 1/11

1 = (V₂/V₁)(1-ξsc₂)/ξsc₂ *(1/10)

10 = (V₂/V₁)* (1/ξsc₂-1) → ξsc₂ = 1/(10*(V₁/V₂)+1)

therefore the extent of reaction varies with the volume reduction according to

ξsc₂ = 1/(10*(V₁/V₂)+1)

since V₁/V₂=2

ξsc₂ = 1/(10*2+1) = 1/21

therefore the decrease in moles of Sulfuryl chloride is

Δnsc/nsc₁ = (ξsc₂-ξsc₁)/(1-ξsc₁) = (1/21-1/11)/(10/11)= (11/21-1)/10 = -1/21 (-4.76%)

6 0

3 years ago

A 1.8 g sample of octane C8H18 was burned in a bomb calorimeter and the temperature of 100 g of water increased from 21.36 C to

melomori [17]

Answer:

HEAT OF COMBUSTION PER GRAM OF OCTANE IS 1723.08 J OR 1.72 KJ/G OF HEAT

HEAT OFF COMBUSTION PER MOLE OF OCTANE IS 196.4 KJ/ MOL OF HEAT

Explanation:

Mass of water = 100 g

Change in temperature = 28.78 °C - 21.36°C = 7.42 °C

Heat capcacity of water = 4.18 J/g°C

Mass of octane = 1.8 g

Molar mass of octane = C8H18 = (12 * 8 + 1 * 18) g/mol= 96 + 18 = 114 g/mol

First is to calculate the heat evolved when 100 g of water is used:

Heat = mass * specific heat capacity * change in temperature

Heat = 100 * 4.18 * 7.42

Heat = 3101.56 J

In other words, 3101.56 J of heat was evolved from the reaction of 1.8 g octane with water.

Heat of combustion of octane per gram:

1.8 g of octane produces 3101.56 J of heat

1 g of octane will produce ( 3101.56 * 1 / 1.8)

= 1723.08 J of heat

So, heat of combustion of octane per gram is 1723.08 J

Heat of combustion per mole:

1.8 g of octane produces 3101.56 J of heat

1 mole of octane will produce X J of heat

1 mole of octane = 114 g/ mol of octane

So we have:

1.8 g of octane = 3101.56 J

114 g of octane = (3101.56 * 114 / 1.8) J of heat

= 196 432.13 J

= 196. 4 kJ of heat

The heat of combustion of octane per mole is 196.4 kJ /mol.

Mass of water = 100 g

Change in temperature = 28.78 °C - 21.36°C = 7.42 °C

Heat capcacity of water = 4.18 J/g°C

Mass of octane = 1.8 g

Molar mass of octane = C8H18 = (12 * 8 + 1 * 18) g/mol= 96 + 18 = 114 g/mol

First is to calculate the heat evolved when 100 g of water is used:

Heat = mass * specific heat capacity * change in temperature

Heat = 100 * 4.18 * 7.42

Heat = 3101.56 J

8 0

3 years ago

Identify the base in the reaction (CH3)3N(aq) + HCl(aq) → (CH3)3NH+(aq) + Cl−(aq) 1. (CH3)3NH+(aq) 2. Cl−(aq) 3. (CH3)3N(aq) 4.

bixtya [17]

Answer:

(CH3)3N(aq)

Explanation:

We have to think of the definition of acid and base in the sense of Brownstead-Lowry. The Brønsted–Lowry theory is an acid–base reaction theory which was proposed independently by Johannes Nicolaus Brønsted and Thomas Martin Lowry in 1923.

A Bronsted-Lowry acid is a chemical species that donates one or more hydrogen ions in a reaction. In contrast, a Bronsted-Lowry base accepts hydrogen ions. When it donates its proton, the acid becomes its conjugate base. A more general approach to the theory is viewing an acid as a proton donor and a base as a proton acceptor.

If we look at the reaction closely, we can see that (CH3)3N(aq) accepted a proton. According to the definition above, we will have to classify (CH3)3N(aq) as a base. Hence the answer.

7 0

3 years ago

What is the equation for determining gas pressure?

Advocard [28]

Answer:

Explanation:

First, let's review the ideal gas law, PV = nRT. In this equation, 'P' is the pressure in atmospheres, 'V' is the volume in liters, 'n' is the number of particles in moles, 'T' is the temperature in Kelvin and 'R' is the ideal gas constant (0.0821 liter atmospheres per moles Kelvin)

8 0

3 years ago

Read 2 more answers

Use Table 1 below to answer the following question: Scientists find a piece of wood that is thought to be from an ancient fire c

mrs_skeptik [129]

Time passed Time passed 14C initially present 14C at end of half-life
(half life)    (Years)
........................................................................................................................
0 0 1,000,000 1,000,000

1 5750     .....    5,00,000

2 11500 .....       2,50,000

3 17250 .....     1,25,000

4 23000 ..... 62,500

Since, wood sample contained 1/16 of current atmospheric concentration of 14C. It means that sample has crossed 4 half-life. Number atoms left are 4 half life = 62,500

6 0

3 years ago