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kari74 [83]
3 years ago
15

Simplify the expression.1. 4(x + 3) =​

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
7 0
It is 1.4x+4.2 you do not need to simplify
fgiga [73]3 years ago
4 0
Your answer is 4x+12
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Consider the ODE, dy dx = y 2 1 + x (2) subject to condition y = 1 when x = 0, use your Euler code from class (modified if neces
makkiz [27]

Answer:

Computation.

Step-by-step explanation:

I'm not really sure if that's the analytical solution of the inital value problem,

because y(0)=11-ln(1-0)(3)=11. Howevwer, let us procede with the given values...

Let us assume that we are going to use euler with n=2 (two steps) and h=0.2(the size of each step)

The update rules of the Euler Methode are

X_i = X_{i-1}+h=X_0+ih

m_i=\dfrac{dY}{dX} \biggr \rvert_{x_i} \\\\Y_{i+1}=m_i\cdot h+y_i

Since the initial value problem tells us that Y=1 when X=0, we know that

X_0=0 and that Y_0=1. Then, we have

X_0=0\\\\X_1=0.2\\\\X_2=0.4

and

Y_0=1\\\\m_0=21 \cdot Y_0 + X_0 \cdot 2=21 \cdot 1 + 0=21\\\\Y_1=0.2 \cdot 21 + 1 =5.2\\\\m_1=21 \cdot Y_1 + X_1\cdot 2=21 \cdot 5.2 + 0.2 \cdot 2=109.6\\ \\Y_2=m_1 \cdot h + Y_1 = 109.6 \cdot 0.2 + 5.2= 27.12

which gives us the points (0,1), (0.2, 5.2) and (0.4, 27.12).

Now, since we want to compare the analyticaland the Euler result, we first compute the value of y=11-ln(1-x)(3) for the values x=0, 0.2 and 0.4. We get that

y(0)=11-\ln(1-0)(3)=11-ln(1)(3)=11\\\\Y(1)=11-\ln(1-0.2)(3)=11.67\\\\Y(2)=11-\ln(1-0.4)(3)=12.53

and we compute Y(i)-Y_i for each i.

It holds

Y(0)-Y_0=11-1=10\\\\Y(1)-Y_1=11.67-5.2=6.47\\\\Y(2)-Y_2=12.53-27.12=-14.59

which tells us that we have a really bad approximation, as I already stated there must be a mistake in the analytical solution since the intial values don't coincide. Also note that the curve that we get using the euler methose is growing faster than the analitical solution.

4 0
3 years ago
Factor the expression (20a+4)-(14a-12)
Klio2033 [76]
2(3a+8) I used photo math, and it gave me a step by step. The top steps are factor the expressions (20a+4)-(14a-12), which is (4(5a+1)-2(7a-6)

7 0
3 years ago
Find a polynomial function f(x) of degree 3 with real coefficients that satisfies the following conditions.
frosja888 [35]

Answer:

The polynomial will be f(x) = \frac{4}{9}x(x - 2)^{2}.

Step-by-step explanation:

The three degree polynomial function f(x) has zeros at x = 0 and at x = 4 having multiplicity 2.

Therefore, (x - 0) and (x - 4)² will be factors of the polynomial f(x).

Hence, the polynomial will be f(x) = Ax(x - 4)² .............. (1), where A is any constant that we have to evaluate.

Now, given that f(5) = 20

So, from the equation (1) we have

20 = A(5)(5 - 2)²

⇒ A = \frac{4}{9}

Therefore, the polynomial will be f(x) = \frac{4}{9}x(x - 2)^{2} (Answer)

4 0
3 years ago
True or false: if x=1, then x>0. If false, give a counterexample.
UkoKoshka [18]
True
because u gotta think about it like that for more then 5 seconds
3 0
3 years ago
Read 2 more answers
The total weight for a family of 4 hippos is 14,007 pounds. The mother hippo
jeyben [28]
The father hippo weighs 6,204 pounds.

You subtract the weight of the other hippos from the total weight of the family to get this.
5 0
4 years ago
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