What is <img src="https://tex.z-dn.net/?f=40%20%5Cdiv%208" id="TexFormula1" title="40 \div 8" alt="40 \div 8" align="absmidd

A particle starts at time t=0 and moves along a number line so that its position, at time t is greater than or equal to zero, is

olga2289 [7]

at t=0
x(0) = (-2)* (-6)^3= 432.
nitial position. At t=2, x(2)=0.
We can see that our particle is moving towards the left on the axis (by getting from 432 to 0
At t>2 and t<6, x(t) <0.
Our particle is still going left - now beyond the y axis
. At t=6, x(6) = 0
since we were left from the y axis (because we were going negative earlier) that means the particle took a right turn this time.
. At t>6, x(t)>0 the particle is still going right and will keep on going to infinity.
6 seconds.is answer hope this helps

4 0

4 years ago

(2x² – 10x-26)÷(x-7)

Maurinko [17]

Answer:

2 • (x2 - 5x - 13)

——————————————————

x - 7

Step-by-step explanation:

I used an online algebra solver then checked it myself.

8 0

4 years ago

Need help

andrey2020 [161]

Answer:

1. 40

2. 40

3. 140

4. 210.5

I tried, hope this helps :)

3 0

3 years ago

I need help of this three, can anyone tell me?

Aleks04 [339]

1. 46 ÷ 5.2= # of inches of rain in El Paso
2. 60-18= #of blocks
#of blocks ÷ 2= # of minutes
3. 61.20-45.95= $$$
$$$ ÷ .15=#of minutes
# of minutes should be answer

5 0

4 years ago

The point A (-7,5) is reflected over the line x = -5, and then is reflected over the line x= 2. What are the coordinates of

liubo4ka [24]

Answer:

(7, 5) is the final reflection of the point.

Step-by-step explanation:

We are given point A(-7, 5) which is first reflected over the line $x= -5$ .

The minimum distance of the point A(-7, 5) from the line $x= -5$ is 2 units across the horizontal path (No change in y coordinate).

Point A lies 2 units on the left side of the line $x= -5$ .

So, its reflection will be 2 units on the right side of $x= -5$ .

Let its reflection be A' which has coordinates as (-5+2,5) i.e. (-3, 5).

Now A'(-3, 5) is reflected on the line $x=2$ .

The minimum distance of the point A'(-3, 5) from the line $x=2$ is 5 units across the horizontal path (No change in y coordinate).

Point A' lies 5 units on the left side of the line $x=2$ .

So, its reflection will be 5 units on the right side of $x=2$ .

Let its reflection be A'' which has coordinates as (2+5, 5) i.e (7, 5) is the final reflection of the point..

Please find attached image.

(7, 5) is the final reflection of the point.

5 0

4 years ago