Question

Help, please!!! What is the mN?

Answer 1

Answer:

61°

Step-by-step explanation:

Given:

∆MNO,

Side MO (n) = 18

MN (o) = 6

m<O = 17°

Required:

m<N

Solution:

Using the sine rule, $\frac{sin N}{n} = \frac{sin O}{o}$ , solve for N.

Plug in the values of M, n, and m

$\frac{sin N}{18} = \frac{sin 17}{6}$

Cross multiply

$6*sin(N) = sin(17)*18$

$6*sin(N) = 0.292*18$

Divide both sides by 6

$\frac{6*sin N}{6} = \frac{0.292*18}{6}$

$sin N = \frac{0.292*18}{6}$

$sin N = \frac{5.256}{6}$

$sin N = 0.876$

$N = sin^-1(0.876)$

$N = 61.16$

m<N ≈ 61°