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timofeeve [1]
3 years ago
6

Help pleaseee ASAP ASAP

Mathematics
2 answers:
Reika [66]3 years ago
6 0

Answer:

SAS

Step-by-step explanation:

two sides are same, and the angles between the sides are same (vertical).

umka21 [38]3 years ago
4 0
Sas two sides are the same .vertical
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Y=x-6 and y=8x+1 need help
Alex73 [517]
8x+1=x-6
7x+1=-6
7x=-7
X=-1
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4 0
3 years ago
Read 2 more answers
Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
Scorpion4ik [409]

let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

4 0
3 years ago
Does anybody like anime ??
ad-work [718]
Of course bro why wouldn’t we like anime
3 0
3 years ago
How do you solve a/7+5/7=2/7
Anton [14]
\frac{a}{7} + \frac{5}{7} = \frac{2}{7} \\ \frac{a + 5}{7} = \frac{2}{7} \\ 7(\frac{a + 5}{7}) = 7(\frac{2}{7})
a + 5 = 2
a + 5 - 5 = 2 - 5
a = -3

Hope this helps! :)
4 0
4 years ago
A spring with a spring constant k of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. It is then st
shutvik [7]

Answer:

Equation of movement y(t)

y(t)=sin(10t-\pi/2)

Amplitude: 1 inch

Period: 0.628 seconds

Step-by-step explanation:

If there is no friction, the amplitude will be the length it was streched from the equilibrium. In this case, this value is 1 inch

A=1\,inch

The period depends on the mass and the spring constant.

The formula for the period is:

T=\frac{1}{f} =\frac{2/pi}{\omega} =2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{1}{100}}=2\pi*0.1=0.628\, s

The model y(t) for the movement of the mass-spring system is

y(t)=A\cdot sin(\omega t +\phi)\\\\A=1\\\\\omega=\sqrt{k/m} =\sqrt{100/1}=10\\\\y(0)=Asin(\phi)=-A\\\\ \phi=arcsin(-1)=-1.571=-\pi/2\\\\\\y(t)=sin(10t-\pi/2)

8 0
4 years ago
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