Answer:
The balls velocity is 1 divided by 3
The given statement "An AED should only be used if a person is too tired to continue with chest compressions" is false.
Answer: Option B
<u>Explanation:</u>
Most people think that they are very tired after applying the compress for 2-3 minutes. When the compressor is tired, it tends to compress more slowly. For this reason, rescuers are advised to do compressions in every 2 min to prevent fatigue and optimise the compressions quality. This should only be done if the person does not show signs of life or is dead, does not respond and breathes normally.
For example, consider you come across the victim in a narrow place and you have two helpers: Rescuer 2 arrives with the AED (automated external defibrillator) and puts it on the opposite side from Rescuer 1, who does chest compressions. Rescuer 2 turns on the AED and fixes the electrodes to the victim's chest, connecting wires to the AED if necessary. Rescuer 1 can continue CPR (Cardiopulmonary resuscitation) by placing electrodes until the victim's heart rate has been analysed.
Answer:
measure the area in which the rider will sit on, then take those measurements to a person who crafts saddles, tell them the exact measurements. then you wait a while until he/she is done then put the saddle on the horse.
Explanation:
Answer:
sorry I am not getting dear friend
D = 497.4x10⁻⁶m. The diameter of a mile of 24-gauge copper wire with resistance of 0.14 kΩ and resistivity of copper 1.7×10−8Ω⋅m is 497.4x10⁻⁶m.
In order to solve this problem we have to use the equation that relates resistance and resistivity:
R = ρL/A
Where ρ is the resistivity of the matter, the length of the wire, and A the area of the cross section of the wire.
If a mile of 24-gauge copper wire has a resistance of 0.14 kΩ and the resistivity of copper is 1.7×10⁻⁸ Ω⋅m. Determine the diameter of the wire.
First, we have to clear A from the equation R = ρL/A:
A = ρL/R
Substituting the values
A = [(1.7×10⁻⁸Ω⋅m)(1.6x10³m)]/(0.14x10³Ω)
A = 1.9x10⁻⁷m²
The area of a circle is given by A = πr² = π(D/2)² = πD²/4, to calculate the diameter D we have to clear D from the equation:
D = √4A/π
Substituting the value of A:
D = √4(1.9x10⁻⁷m²)/π
D = 497.4x10⁻⁶m