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3 years ago

If you are given time and distance, you can determine power if you know force. watts. energy. joules.

Physics

2 answers:

lesantik [10]3 years ago

5 0

the answer is not joules but thanks for your answer

DENIUS [597]3 years ago

4 0

If you are given time and distance, you can determine power if you know force. watts. energy. joules.

Answer is joules.

Power is defined as the rate of doing work. Hence power = work / time then you obtain watts. Work is the product of force and displacement (distance). Hence in formula, w = F x s. In which the S.I unit of work is joule in the product. This is what you have to obtain in order to calculate for power.

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How has the diversity of mammals changed through time do you see any realtionship with how reptiles diversity had changed

sweet [91]

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3 years ago

Which measure of dispersion indicates the extent to which each individual score in a data set varies from the mean of that set?

vichka [17]

Answer:

Option 2 - Standard deviation

Explanation:

To find : Which measure of dispersion indicates the extent to which each individual score in a data set varies from the mean of that set?

Solution :

Standard deviation is defined as,

It is a mathematical measure that is used to evaluate the difference between the mean value of a set of number and each value in the group.

It is calculated as the square root of variance by determining the variation between each data point relative to the mean.

The measure of dispersion that indicates how much scores in a sample vary around the mean of the sample is the standard deviation.

Therefore, option 2 is correct.

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3 years ago

How many protons neutrons and electrons are in fluorine and in bromine

AfilCa [17]

Flourine:
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7 0

3 years ago

The density of Mercury is 1.36 × 10 by 4 Kgm - 3 at 0 degrees. Calculate its value at 100 degrees and at 22 degrees. Take cubic

Drupady [299]

a) Density at 100 degrees: $1.34\cdot 10^4 kg/m^3$

Explanation:

The density of mercury at 0 degrees is $d=1.36\cdot 10^4 kg/m^3$

Let's take 1 kg of mercury. Its volume at 0 degrees is

$V=\frac{m}{d}=\frac{1 kg}{1.36\cdot 10^4 kg/m^3}=7.35\cdot 10^{-5} m^3$

The formula to calculate the volumetric expansion of the mercury is:

$\Delta V= \alpha V \Delta T$

where

$\alpha=180\cdot 10^{-6} K^{-1}$ is the cubic expansivity of mercury

V is the initial volume

$\Delta T$ is the increase in temperature

In this part of the problem, $\Delta T=100 C-0 C=100 C=100 K$

So, the expansion is

$\Delta V= \alpha V \Delta T=(180\cdot 10^{-6} K^{-1})(7.35\cdot 10^{-5} m^3)(100 K)=1.3\cdot 10^{-6} m^3$

So, the new density is

$d'=\frac{m}{V+\Delta V}=\frac{1 kg}{7.35\cdot 10^{-5} m^3+1.3\cdot 10^{-6} m^3}=1.34\cdot 10^4 kg/m^3$

b) Density at 22 degrees: $1.355\cdot 10^4 kg/m^3$

We can apply the same formula we used before, the only difference here is that the increase in temperature is

$\Delta T=22 C-0 C=22 C=22 K$

And the volumetric expansion is

$\Delta V= \alpha V \Delta T=(180\cdot 10^{-6} K^{-1})(7.35\cdot 10^{-5} m^3)(22 K)=2.9\cdot 10^{-7} m^3$

So, the new density is

$d'=\frac{m}{V+\Delta V}=\frac{1 kg}{7.35\cdot 10^{-5} m^3+2.9\cdot 10^{-7} m^3}=1.355\cdot 10^4 kg/m^3$

8 0

3 years ago

The emission of x rays can be described as an inverse photoelectric effect.

timama [110]

Answer:

The potential difference through which an electron accelerates to produce x rays is $1.24\times 10^4\ volts$ .

Explanation:

It is given that,

Wavelength of the x -rays, $\lambda=0.1\ nm=0.1\times 10^{-9}\ m$

The energy of the x- rays is given by :

$E=\dfrac{hc}{\lambda}$

The energy of an electron in terms of potential difference is given by :

$E=eV$

So,

$\dfrac{hc}{\lambda}=eV$

V is the potential difference

e is the charge on electron

$V=\dfrac{hc}{e\lambda}$

$V=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{1.6\times 10^{-19}\times 0.1\times 10^{-9}}$

V = 12431.25 volts

$V=1.24\times 10^4\ volts$

So, the potential difference through which an electron accelerates to produce x rays is $1.24\times 10^4\ volts$ . hence, this is the required solution.

4 0

3 years ago