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3 years ago

What is the answer to this please?

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

4 0

The answer of the rotational symmetry is B, (6)

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Please help! Question posted above ^

emmainna [20.7K]

Answer:

( x^2 - 6 )^2

Step-by-step explanation:

x^4 -12x^2 +36

Find one factor
Factor by grouping

(x^2 - 6x) (x^2 - 6x)

*solution* ( x^2 - 6 )^2

8 0

3 years ago

Find the area of this parallelogram

gulaghasi [49]

Answer:

140 cm²

Step-by-step explanation:

The height of the parallelogram is 10cm . And its base is 14cm .We know that the area of parallelogram is product of base and height .

⇒ Area = base × Height

⇒ Area = 14cm × 10cm

⇒ Area = 140 cm² .

<h3>Hence the area of the parallelogram is 140 cm² .</h3>

7 0

3 years ago

Please help In geometry homework

bezimeni [28]

The surface area of this hexagonal prism is approximately 313.2cm^2

Hope this helps

7 0

3 years ago

What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.

Paul [167]

Answer:

1.60 $ft^{2}$

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = $\pi$ $r^{2}$

So that,

for the inner part of the pipe,

r = $\frac{diameter}{2}$

= $\frac{5}{2}$

= 2.5 feet

Area of the inner part of the pipe = $\pi$ $r^{2}$

= 3.14 x $(2.5)^{2}$

= 19.625

Are of the inner part of the pipe is 19.63 $ft^{2}$ .

Total diameter of the pipe = 5 + 0.2

= 5.2 feet

r = $\frac{5.2}{2}$

= 2.6 feet

Area of the pipe = $\pi$ $r^{2}$

= 3.14 x $(2.6)^{2}$

= 21.2264

Area of the pipe is 21.23 $ft^{2}$ .

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

= 21.2264 - 19.625

= 1.6014

The cross sectional area of the cement pipe is 1.60 $ft^{2}$ .

6 0

3 years ago

Write a polynomial in standard form that represents the area of the shaded region.

mr_godi [17]

Area of rectangle is $2x^2+x-45$

Step-by-step explanation:

Given:

Length of rectangle = 2x-9

Width of rectangle = x+5

Required:

Area of rectangle

Formula:

$Area\,\,of\,\,rectangle=Length*Width$

Putting values of length and width:

$Area\,\,of\,\,rectangle=Length*Width\\Area\,\,of\,\,rectangle=(2x-9)(x+5)\\Area\,\,of\,\,rectangle=2x(x+5)-9(x+5)\\Area\,\,of\,\,rectangle=2x^2+10x-9x-45\\Area\,\,of\,\,rectangle=2x^2+x-45$

So, Area of rectangle is $2x^2+x-45$

Keywords: Area of rectangle

Learn more about Area of rectangle at:

#learnwithBrainly

3 0

3 years ago