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aalyn [17]
3 years ago
8

For anyone who plays warzone, do you think the hdr has earned its spot back after the spr nerf? Be completely honest plz.​

Computers and Technology
1 answer:
qwelly [4]3 years ago
8 0

Answer:

Yes I do honestly : )

What about you ??

Explanation:

Hope this helped : )

Since I was the first one may i have brainiest : )

You might be interested in
Write a telephone lookup program. Read a data set of 1,000 names and telephone numbers from a file that contains the numbers in
morpeh [17]

Answer:

See explaination

Explanation:

PhoneLookup.java

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class PhoneLookup

{

public static void main(String[] args) throws IOException

{

Scanner in = new Scanner(System.in);

System.out.println("Enter the name of the phonebook file: ");

String fileName = in.nextLine();

LookupTable table = new LookupTable();

FileReader reader = new FileReader(fileName);

table.read(new Scanner(reader));

boolean more = true;

while (more)

{

System.out.println("Lookup N)ame, P)hone number, Q)uit?");

String cmd = in.nextLine();

if (cmd.equalsIgnoreCase("Q"))

more = false;

else if (cmd.equalsIgnoreCase("N"))

{

System.out.println("Enter name:");

String n = in.nextLine();

System.out.println("Phone number: " + table.lookup(n));

}

else if (cmd.equalsIgnoreCase("P"))

{

System.out.println("Enter phone number:");

String n = in.nextLine();

System.out.println("Name: " + table.reverseLookup(n));

}

}

}

}

LookupTable.java

import java.util.ArrayList;

import java.util.Collections;

import java.util.Scanner;

/**

A table for lookups and reverse lookups

*/

public class LookupTable

{

private ArrayList<Item> people;

/**

Constructs a LookupTable object.

*/

public LookupTable()

{

people = new ArrayList<Item>();

}

/**

Reads key/value pairs.

atparam in the scanner for reading the input

*/

public void read(Scanner in)

{

while(in.hasNext()){

String name = in.nextLine();

String number = in.nextLine();

people.add(new Item(name, number));

}

}

/**

Looks up an item in the table.

atparam k the key to find

atreturn the value with the given key, or null if no

such item was found.

*/

public String lookup(String k)

{

String output = null;

for(Item item: people){

if(k.equals(item.getName())){

output = item.getNumber();

}

}

return output;

}

/**

Looks up an item in the table.

atparam v the value to find

atreturn the key with the given value, or null if no

such item was found.

*/

public String reverseLookup(String v)

{

String output = null;

for(Item item: people){

if(v.equals(item.getNumber())){

output = item.getName();

}

}

return output;

}

}

Item.java

public class Item {

private String name, number;

public Item(String aName, String aNumber){

name = aName;

number = aNumber;

}

public String getName(){

return name;

}

public String getNumber(){

return number;

}

}

input.txt

Abbott, Amy

408-924-1669

Abeyta, Ric

408-924-2185

Abrams, Arthur

408-924-6120

Abriam-Yago, Kathy

408-924-3159

Accardo, Dan

408-924-2236

Acevedo, Elvira

408-924-5200

Acevedo, Gloria

408-924-6556

Achtenhagen, Stephen

408-924-3522

Note: Replace all the "at" with at symbol

4 0
3 years ago
What is the name of the interface that uses graphics as compared to a command-driven interface?
bonufazy [111]
Answer = GUI (Graphical User Interface)
4 0
3 years ago
In GamePoints' constructor, assign teamWhales with 500 and teamLions with 500. #include using namespace std; class GamePoints {
xxMikexx [17]

Answer:

Here is the GamePoints constructor:

GamePoints::GamePoints() :

/* Your code goes here */

{

teamLions = 500;

teamDolphins = 500;

}    

Explanation:

Here is the complete program:

#include  //to use input output functions

using namespace std; //to identify objects like cin cout

class GamePoints {  //class GamePoints

   public: GamePoints(); // constructor of GamePoints class

   void Start() const;  //method of GamePoints class

   private: //declare data members of GamePoints class

   int teamDolphins; // integer type private member variable of GamePoints

   int teamLions; }; // integer type private member variable of GamePoints

   GamePoints::GamePoints()  //constructor

    { teamLions = (500), teamDolphins= (500); }   //assigns 500 to the data members of teamLions  and teamDolphins of GamePoints class

   void GamePoints::Start() const    { //method Start of classs GamePoints

       cout << "Game started: Dolphins " << teamDolphins << " - " << teamLions << " Lions" << endl; }  //displays the values of teamDolphins and teamLions i.e. 500 assigned by the constructor

       int main() //start of main() function

       { GamePoints myGame;  // creates an object of GamePoints class

       myGame.Start(); //calls Start method of GamePoints class using the object

       return 0; }

The output of the program is:

Game started: Dolphins 500 - 500 Lions                    

8 0
3 years ago
There have not been any changes to instruments or music in the last 50 years. The technology in music is still the same.
aliya0001 [1]

Answer:

False i hope this is rigth

7 0
2 years ago
A digital computer has a memory unit with 16 bits per word. The instruction set consists of 72 different operations. All instruc
OLga [1]

Answer:

a. 7 bits b. 9 bits c. 1 kB d. 2¹⁶ - 1

Explanation:

a. How many bits are needed for the opcode?

Since there are 72 different operations, we require the number of bits that would contain 72 different operations. So, 2ⁿ ≥ 72

72 = 64 + 8 = 2⁶ + 8

Since n must be an integer value, the closest value of n that would contain 72 different operations is n = 7. So, 2⁷ = 128

So, we require 7 bits for the opcode.

b. How many bits are left for the address part of the instruction?

bits left = bits per word - opcode bit = 16 - 7 = 9 bits

c. What is the maximum allowable size for memory?

Since there are going to be 2⁹ bits to addresses each word and 16 bits  for each word, the maximum allowable size for memory is thus 2⁹ × 16 = 512 × 16 = 8192 bits.

We convert this to bytes

8192 bits × 1 byte/8 bits = 1024 bytes = 1 kB

d. What is the largest unsigned binary number that can be accommodated in one word of memory?

Since the number go from 0 to 2¹⁶, the largest unsigned binary number that can be accommodated in one word of memory is thus

2¹⁶ - 1

6 0
3 years ago
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