Answer:
- Agree on aims concerning the application.
- Read your end users.
- Take your IT partners toward the conversations in the beginning.
- Program for various announcements.
- Choose the technology which you know and will be able to continue.
Explanation:
You should always keep the above five points while developing an app. You should keep your goals in mind that what kind of app you are going to develop and you are taking surveys from end users that what they want after some time in different cycles. Your team should discuss your project time by time about the progress of an app. Your project should be a long term and should almost cover all kind of users.
Answer:
Very few recorders have built-in microphones that are useful for field reporting. Does the recorder have XLR (professional grade) input, Tip-Ring Sleeve (TRS) input or just a mini jack? Format – There are two types of audio files: compressed and uncompressed. Cheap audio recorders will compress all of the audio it captures.
Explanation:
hope this helps mark as brainiest.
True; synchronous means existing or occurring at the same time (I really don't know if that's a question but oh well)
Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}
