Question

Carlos has \dfrac45 5 4 ​ start fraction, 4, divided by, 5, end fraction of a tank of fuel in his car. He uses \dfrac{1}{10} 10 1 ​ start fraction, 1, divided by, 10, end fraction of a tank per day.

Answer 1

Answer:

8 days.

Step-by-step explanation:

Consider the question: Carlos has 4/5 of a tank of fuel in his car. He uses 1/10 of a tank per day. How many days will his fuel last?

To find the number of days Carlos' fuel last, we need to divide amount of fuel in tank by amount of fuel used per day as:

$\text{The number of days Carlos' fuel will last}=\frac{4}{5}\div\frac{1}{10}$

Convert into multiplication problem by flipping the second fraction as:

$\text{The number of days Carlos' fuel will last}=\frac{4}{5}\times \frac{10}{1}$

$\text{The number of days Carlos' fuel will last}=\frac{4}{1}\times \frac{2}{1}$

$\text{The number of days Carlos' fuel will last}=8$

Therefore, Carlos's fuel will last for 8 days.

Answer 2

Answer:

8

Step-by-step explanation: