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Usimov [2.4K]
3 years ago
15

Please help me with these math problems!!

Mathematics
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:

75

Step-by-step explanation:

yan lang po ang kaya ko

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Yoo i need help with this stuff
romanna [79]
There are 1760 yards in a mile
2 miles = 3520 yards

he runs 80 yards per practice (4×20)
3520÷80= 44

he needs to do the practice 44 times.

--------------

There are 128 oz in a gallon
he brought two gallons, meaning 256 oz
each cup holds 8 oz

256 ÷ 8 = 32

he can serve 32 cups.
7 0
3 years ago
A group of transfer bound students wondered if they will spend the same mean amount on texts and supplies each year at their fou
Jet001 [13]

Answer:

We accept H₀. We don´t have enough evidence to support the difference between the two means

Step-by-step explanation:

Group 1 : Comunity College

Sample:

size  :   n₁  = 54

Sample mean    x₁  = 947

Sample standard deviation     s₁ = 254

Group 2 : Local University

Sample

size  :  n₂  =  66

Sample mean :  x₂  = 1011

Sample standard deviation    s₂  =  87

Significance level  α  = 0,05      α  =  5 %      CI = 95 %

Both samples are with n> 30 so we can use z table for the test

from z-table we find  z(c)  =  1,96

The problem statement establishes to run a hypothesis test to determine if the means are statistically the same  ( or different) then we use two-tail-test

Hypothesis Test

Null Hypothesis                        H₀             x₁   -  x₂  = 0 or    x₁  = x₂

Alternative hypothesis             Hₐ             x₁  -  x₂  ≠  0  or    x₁ ≠ x₂

To calculate

z(s)  =  (  x₁   -  x₂  ) / √ s₁²/n₁  + s₂²/n₂ )

z(s)  =  947  -  1011 / √  (254)²/54   +  (87)² / 66

z(s) = -  64  /√ 1194,74  +  114,68

z(s) =  - 64  / 36,185

z(s) =  - 1,77

Comparing modules of  |z(c)|  and |z(s)|

z(s) < z(c)

Then z(s) is in the acceptance region we accept H₀ . There is not enough evidence to support differences in the means of the two groups

3 0
3 years ago
Can someone like an ace or very good at math help me
eimsori [14]
Supplementary angles , when added, = 180
complimentary angles, when added, = 90

< AQC + < GQC = 180.....supplementary
< BQD + < DQE = 90.......complimentary
< CQE + < EQF = 90.......complimentary
< GQF , < FQE.....neither
< BQC + < DQC = 90....complimentary

< W and < X are supplementary...
if < W = 37, then < X = (180 - 37) = 143

< S and < T are complimentary
if < S = 64, then < T = (90 - 64) = 26

< C and < D are supplementary
if < C = 83, the < D = (180 - 83) = 97

cant read all of the last one.....but if they are complimentary, and 
< U = 41, then the other angle is : (90 - 41) = 49


4 0
4 years ago
The 'Queen Mary' used to sail across the Atlantic Ocean The ships usual speed was 33 miles per hour. On average, the ship used f
makkiz [27]
13403.07692307692 i think is the answer because you multiply 5280 by 33 and then divide by 13.
6 0
4 years ago
Solve for b. 3b+2(b-3)=4
aleksandrvk [35]
The answer is b=2 because yea
3 0
4 years ago
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