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Ainat [17]
3 years ago
7

Find either of the values of x 2x^2+3x-2=3

Mathematics
1 answer:
Serjik [45]3 years ago
8 0

Answer:

x = 1 or x = -5/2

Step-by-step explanation:

Solve for x over the real numbers:

2 x^2 + 3 x - 2 = 3

Divide both sides by 2:

x^2 + (3 x)/2 - 1 = 3/2

Add 1 to both sides:

x^2 + (3 x)/2 = 5/2

Add 9/16 to both sides:

x^2 + (3 x)/2 + 9/16 = 49/16

Write the left hand side as a square:

(x + 3/4)^2 = 49/16

Take the square root of both sides:

x + 3/4 = 7/4 or x + 3/4 = -7/4

Subtract 3/4 from both sides:

x = 1 or x + 3/4 = -7/4

Subtract 3/4 from both sides:

Answer: x = 1 or x = -5/2

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3 years ago
HELP ME PLEASE<br> Solve for x: -6 – 5x = 29
Lynna [10]

Answer:

x = -7

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

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First, add 6 to both sides of the equation:

-5x - 6 = 29

-5x - 6  (+6) = 29 (+6)

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Next, divide -5 from both sides of the equation:
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x = -7

-7 is your answer for x.

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4 0
2 years ago
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Solve the quadratic equation:<br> 3x^2+x-5=0
adell [148]

3x²+x-5=0

a = 3, b = 1, c= -5

-> ∆ ( delta ) = b²-4ac = 61 > 0

-> x1 =( -b+√∆ )÷ 2a =...

x2 = (-b-√∆)÷2a =...

p/s: do your teachers teach you how to use ∆ ( delta ) in maths calculation ? i live in europe and our teachers teach us that way. however, it is a rịght and fast way. you should learn it.

4 0
3 years ago
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