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Elan Coil [88]
3 years ago
12

-5/4 divided by 2 3/4

Mathematics
1 answer:
MArishka [77]3 years ago
6 0
-5/11 is what I got with a fraction calculator.
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Mhanifa please help fast
Shkiper50 [21]

Answer:

<h3>Q 17</h3>

a is supplementary with 36 and b is supplementary with 113.

  • a = 180 - 36 = 144
  • b = 180 - 113 = 67

Correct choice is D

<h3>Q 2</h3>
  • LM = 1/2(AB + DC) = 1/2(46 + 125) = 85.5
<h3>Q 3</h3>

Diagonals of a rectangle are congruent

  • KM = LN
  • 6x + 16 = 49
  • 6x = 33
  • x = 33/6
  • x = 5.5

Correct choice is A

8 0
3 years ago
Tank a has a capacity of 9.5 gallons. 6 1/3 gallons of the tank's water are poured out. how many gallons of water are left in th
Advocard [28]

Answer:

Water left in tank is 3\frac{1}{6} gallons.

Step-by-step explanation:

Given :

Capacity of tank = 9.5 gallons  =\frac{95}{10}

Water taken out of tank =6\frac{1}{3}=\frac{19}{3} gallons

We have to find the water left in the tank.

Water left in the tank = Total capacity of tank - water taken out of tank

                                    =\frac{95}{10}-\frac{19}{3}

Taking LCM of (3,10)= 30

\Rightarrow \frac{95 \times 3-19 \times10}{30}

Solving further, we get,

\Rightarrow \frac{285-190}{30}

\Rightarrow \frac{95}{30}=\frac{19}{6}=3\frac{1}{6}

Thus, Water left in tank is 3\frac{1}{6} gallons..

5 0
3 years ago
Read 2 more answers
What is the area of the triangle in the diagram?
Vladimir [108]

1/2sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))

The area of a triangle is equal to 1/2bh (one half base times height). Since this is a right triangle, the base and height are the two legs connected to the 90* angle. To find the values of these sides, we will use Pythagorean Theorem, root a squared plus b squared.

Short leg: <x(1),y(1)>

This leg can be seen as the hypotenuse of an invisible right triangle. The x value, x(1), is how far over the x value has gone from the origon at x=0. Imagine a leg alone the x-axis, going from (0,0) to (x(1),0). The y value of the point, y(1), works the same way. This leg will go from our previous mark at (x(1),0) to the point (x(1),y(1)). This shows that the short leg of the main triangle is the hypotenuse, with a height of y(1) and base of x(1). Pythagoreum Theorem shows that the length of this leg is equal to sqrt(x_1^2+y_1^2).

Long leg: <x(2), y(2)>

The same process works here, giving us sqrt(x_2^2+y_2^2).

Now for the area, we have the b and h values. Our equation reads 1/2sqrt(x_1^2+y_1^2)sqrt(x_2^2+y_2^2).

But we can simplify this (yay). The two square roots can be written together as sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))

So the correct answer is 1/2sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))

5 0
3 years ago
Read 2 more answers
2x+3y=11<br> Solve for x and y
irga5000 [103]
To solve this equation you have to isolate one variable, first we will solving for x, then for y.

Solving for x

2x+3y=11

2x=11-3y

\boxed{\boxed{x=\frac{11}{2}-\frac{3}{2}*y}}

Solving for y

2x+3y=11

3y=11-2x

\boxed{\boxed{y=\frac{11}{3}-\frac{2}{3}*x}}
6 0
3 years ago
What is the equation of the following line written in general form?
strojnjashka [21]
Eq. of line through (1,2) and (4,5) is
y-y1= \frac{y2-y1}{x2-x1} (x-x1),&#10;y-2= \frac{5-2}{4-1} (x-1)y-2= \frac{3}{3} (x-1)&#10;y-2=x-1&#10;y-2-x+1=0&#10;y-x-1=0
x-y+1=0
4 0
3 years ago
Read 2 more answers
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