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Keith_Richards [23]
3 years ago
12

Solve the system of linear equations below.

Mathematics
1 answer:
Alchen [17]3 years ago
5 0

Answer:

The answer to your question is letter A. x = 0, y = 2/3

Step-by-step explanation:

Equation 1        2x + 3y = 2

Equation 2          x + 6y = 4

Solve the system of equations by elimination

- Multiply equation 2 by -2

                          2x + 3y = 2

                     -2(  x + 6y = 4)

                          2x + 3y = 2

                        -2x - 12y = -8

                           0  - 9y = -6

                                    y = -6/-9

                                   y = 2/3

. Find x

                          2x + 3(2/3) = 2

                          2x + 2 = 2

                          2x = 2 - 2

                          2x = 0

                            x = 0/2

                           x = 0

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Answer:

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Step-by-step explanation:

The given equations are :

y^2+x^2=53\ ....(1)\\\\y-x=5\ ...(2)

Squaring both sides of equation (2)

(y-x)^2=5^2\\\\y^2+x^2-2xy=25\\\\53-2xy=25\ \text{from equation (1)}\\\\2xy=53-25\\\\2xy=28\\\\xy=14\ ...(3)

Put the value of y from equation (2)

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Put the value of x in equation (2)

y-x = 5

y = 5+x

= 5+2

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Hence, the solution of the given equations are (2,7).

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