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Mrac [35]
3 years ago
5

NO LINKS

Mathematics
1 answer:
Olin [163]3 years ago
7 0

Answer:

y = 3.5X - 6921.2

Step-by-step explanation:

Given the data :

X :

1990

1992

1994

1996

1996

Y :

45

51

57

61

75

Using an online regression calculator ; the regression model obtained is : y = 3.5X - 6921.2

Where ; slope = 3.5 ; intercept = - 6921.2

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The distance of my room is 48feet the width is 11 what is the length of my room
vfiekz [6]

Answer:4.36?

Step-by-step explanation:

distance or area?

A=lw

48=11L

4.36=l

6 0
3 years ago
What are the coordinators of the vertex of the graph of the function -2(x-1)^2 = y+5
mamaluj [8]
The answer is, (1, -5)... 
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3 years ago
Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
  • 4 must be related with 4

For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

5 0
3 years ago
Simplify the polynomial by combining like terms. 3.63x2 - 4.54x + 7.96x2 +9.85 -3.12x​
Brums [2.3K]

Answer:

11.59x² -7.66x + 9.85

Step-by-step explanation:

3.63x² - 4.54x + 7.96x² +9.85 -3.12x​

11.59x² -7.66x + 9.85

7 0
3 years ago
Read 2 more answers
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