Anyone Who UNDERSTANDS THIS??????

Mathematics

1 answer:

MrRissso [65]3 years ago

6 0

1. The exponent will be a negative number.

2. The exponent will be a positive numbers.

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One question simple please help

igor_vitrenko [27]

Answer:

$y = \frac{1}{3}x - 9$

Step-by-step explanation:

Standard equation of a line is y = mx + b, where m is the slope.

Given line y = - 3x + 78, slope, m₁ = -3

To find the line perpendicular to the given line.

The lines are perpendicular to each other if the product of their slopes = - 1

That is,

$m_1 \times m_2 = -1$

So the slope of new line is

$-3 \times m_2 = -1\\\\m_2 = \frac{-1}{-3} = \frac{1}{3}$

$Therefore , equation \ of \ new \ line \ \\\\(y - y_1) = m_2(x - x_1) , where \ (x_1 , y_1) = (9, -6 )\\\\(y - (-6))= \frac{1}{3}(x -9)\\\\y + 6 = \frac{1}{3} x - 3\\\\y = \frac{1}{3}x -3-6\\\\y = \frac{1}{3}x -9\\\\$

7 0

3 years ago

What is the product of (1.9*10^-3)(2*10^4)

RoseWind [281]

Answer:

to solve use the distributive property and multiply

Step-by-step explanation:

I'm sorry I do not have the product

4 0

3 years ago

Read 2 more answers

Simplify the trigonometric expression sin(4x)+2 sin(2x) using Double-Angle

drek231 [11]

Answer:

${ \bf{ = \sin(4x) + 2 \sin(2x) }} \\ = { \bf{2 \sin(2x) \cos(2x) + 4 \sin(x) \cos(x) }} \\ { \bf{ = 4 \sin(x) \cos(x) . ({ \cos }^{2} x - { \sin}^{2} }x) + 4 \sin(x) \cos(x) } \\ = { \bf{4 \sin(x) \cos(x) ( { \cos }^{2}x - { \sin }^{2}x + 1) }} \\ = { \bf{4 \sin(x) \cos(x) }(2 { \cos }^{2} x)} \\ = { \bf{8 \sin(x) { \cos}^{3}x }}$