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2 years ago

sean sold 4 more boxes of candy for the school fundraiser than Chris. The sum of the boxes that they sold was 22

Mathematics

2 answers:

sweet-ann [11.9K]2 years ago

5 0

If it was asking for the amount that Chris made, the answer would be 18.

Hope this helps!<3

Sveta_85 [38]2 years ago

3 0

Set up an equation.

x+x+4=22

the varibles x are the unknown number of boxes. the first x is Chris amount and the second is Seans amount.

Isolate the variable:

x+x+4=22

2x+4=22

2x=18

x=9

Chris has 9 boxes.

Add 4 to the variable to get Seans amount:

9+4=13

Sean has 13 boxes

To check your answer add the results together to get the correct sum.

9+13=22

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Find the value of x .

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Answer:

$x=18$

Step-by-step explanation:

$(4x-11)\\(2x+25)$

According to the Alternate Exterior Angles Theorem, "when two lines are cut by a transversal, the resulting alternate exterior angles are congruent."

This means that the two expressions above are to be set equal to each other because they are representative of two alternate exterior angles, which are congruent:

$4x-11=2x+25$

Add $11$ to both sides of the equation:

$4x=2x+36$

Subtract $2x$ from both sides of the equation:

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Divide both sides of the equation by the coefficient of $x$ , which is $2$ :

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Check your work by substituting $18$ for $x$ in the initial equation:

$4(18)-11=2(18)+25$

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Step-by-step explanation:

The given matrix addition is

$B+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

We need to find the elements of matrix B.

Let $B=\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}$

Substitute the value of matrix.

$\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

After addition of two matrix we get

$\begin{bmatrix}b_{11}+15&b_{12}-7&b_{13}+4\\ b_{21}+0&b_{22}+1&b_{23}+2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

On equating both sides.

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Therefore, the elements of matrix B are $b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0$ .

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