Which triangle has 0 reflectional symmetries?
2 answers:
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Answer:
D)4x + 6/(x + 1)(x - 1)
Step-by-step explanation:
A field is basically a rectangle, so to find the perimeter of our field we are using the formula for the perimeter of a rectangle
where
is the perimeter
is the length
is the width
We know from our problem that the field has length 2/x + 1 and width 5/x^2 -1, so and
.
Replacing values:
Notice that the denominator of the second fraction is a difference of squares, so we can factor it using the formula where
is the first term and
is the second term. We can infer that
and
. So,
. Replacing that:
We can see that the common denominator of our fractions is . Now we can simplify our fraction using the common denominator:
We can conclude that the perimeter of the field is D)4x + 6/(x + 1)(x - 1).