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Verizon [17]
3 years ago
7

How many 30° angles does it take to make a full turn?

Mathematics
1 answer:
sergejj [24]3 years ago
8 0
360 degrees is a full turn, so if you multiply 30 degreed by 12, you go around in a circle.
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Find the perimeter of the stained-glass window if each small square is 6 in. on<br> a side.
mel-nik [20]

Answer:

the answer is B . 72√2 look at the picture I added

8 0
2 years ago
What is the value of the expression below?<br><br> |-12|
Anit [1.1K]

Answer:

the absolute value is 12

Step-by-step explanation:

the absolute value is 12 since that is the distance from 0.

4 0
2 years ago
Read 2 more answers
the radius of wheel of a bicycle is 40 cm. taking pie =3.14, a)find tthe circumference of the wheel.b) find the distance covered
monitta

Answer:

a)=251.2 cm    b)=50240 cm

Step-by-step explanation:

a) The formula for calculating the circumference of a circle is c=d*pie, where D is the diameter of the circle.

Therefore, C = 2 * 40 * 3.14 = 251.2 cm

b) The distance covered by 200 revolutions of the wheel is 200 times the circumference, 200*251.2=50240 cm.So to think about this we can assume that there is a point A on the wheel, the distance that point A travels when it rotates 200 times.

6 0
3 years ago
What is the measure of angle C? 38° 76 degrees 90° 152°
Taya2010 [7]

Answer:

The answer is 38

Step-by-step explanation:

7 0
3 years ago
Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2
zlopas [31]

Answer:

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de f(x) = x^{3}-2\cdot x^{2}-2.

Step-by-step explanation:

Un par ordenado es un elemento de la forma (x,f(x)), donde x es un elemento del dominio de la función, mientras f(x) es la imagen de la función evaluada en x. Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:

La imagen de la función existe para un elemento dado del dominio. Esto es:

x \rightarrow f(x)

Dado que f(x) es una función polinómica, existe una imagen para todo elemento x. Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:

x = 0

f(0) = 0^{3}-2\cdot (0)^{2}-2

f(0) = -2

(0, -2) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

x = 1

f(1) = 1^{3}-2\cdot (1)^{2}-2

f(1) = -3

(1, -3) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

x = 2

f(2) = 2^{3}-2\cdot (2)^{2}-2

f(2) = -2

(2, -2) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

x = 3

f(3) = 3^{3}-2\cdot (3)^{2}-2

f(3) = 7

(3, 7) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de f(x) = x^{3}-2\cdot x^{2}-2.

6 0
3 years ago
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