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Trava [24]
2 years ago
9

A watercolor painting is 23 inches long by 11 inches wide. Ramon makes a border around the watercolor painting by making a mat t

hat adds 1 inch to each side of the length and the width. What is the area of the mat?
Mathematics
1 answer:
erik [133]2 years ago
4 0

Answer:

288 inches ²

Step-by-step explanation:

Water color painting

Length = 23 inches

Width = 11 inches

Mat that adds 1 inch to each side of the length and the width

Mat

Length = 23 + 1 = 24 inches

Width = 11 + 1 = 12 inches

What is the area of the mat?

Area of the mat = length × width

= 24 inches × 12 inches

= 288 inches ²

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A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot
Olegator [25]

Answer:

The ratio of the drag coefficients \dfrac{F_m}{F_p} is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, c_{m} = The drag coefficient of the prototype, c_{p}

The medium of the test for the model, \rho_m = The medium of the test for the prototype, \rho_p

The drag force is given as follows;

F_D = C_D \times A \times  \dfrac{\rho \cdot V^2}{2}

We have;

L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m

Therefore;

\dfrac{L_p}{L_m}  = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2

\dfrac{L_p}{L_m}  =\dfrac{17}{1}

\therefore \dfrac{L_p}{L_m}  = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{c_p \times A_p \times  \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times  \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}

\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3

\dfrac{F_m}{F_p}  = \left( \left\dfrac{1}{17} \right)^3= (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients \dfrac{F_m}{F_p} ≈ 0.0002.

5 0
2 years ago
Evaluate 7m+2n-8p/n m=4, n=2, and p=1.5
Firlakuza [10]

Steps to solve:

7m + 2n - 8p/n

~Substitute

7(4) + 2(2) - 8(1.5)/2

~Simplify

28 + 4 - 12/2

~Simplify

28 + 4 - 6

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32

~Subtract

26

Best of Luck!

4 0
3 years ago
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Triss [41]
24 is greater than 16. Or in mathematical terms 24 > 16
7 0
3 years ago
Read 2 more answers
Which relationship describes angles 1 and 2?
Vikki [24]
Vertical angels is the answer
8 0
2 years ago
Can somebody help me with this ?? :)
Alex777 [14]

Answer:

Your answer would be D, the equation is a function because it is a polynomial and all polynomials are functions.

Step-by-step explanation:

I like to remember that polynomials have no negative , fraction exponents and no division. In this case everything is positive so I knew it was a polynomial , and like the answer says all polynomials are functions !

Hope this helped

7 0
3 years ago
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