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yKpoI14uk [10]
3 years ago
5

5.3 liters to milliters​

Mathematics
2 answers:
vfiekz [6]3 years ago
8 0
5,300

Your welcome :)
Dominik [7]3 years ago
7 0

Answer:

5300 milliliters​

Step-by-step explanation:

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The inches of rainfall in the rainforest is represented by the function f(x) = 3(x-2)+ 4. What is the average rate of change bet
nata0808 [166]

Answer:

The average rate of change of rainfall in the rainforest between 2nd year and 6th year = <u>3 inches</u>

Step-by-step explanation:

Given function representing inches of rainfall:

f(x)=3(x-2)+4

To find the average rate of change between the 2nd year and the 6th year.

Solution:

The average rate of change between interval [a,b] is given as :

\frac{f(b)-f(a)}{b-a}

For the given function we need to find the average rate of change between 2nd year and 6th year. [2,6]

So, we have:

f(2)=3(2-2)+4=3(0)+4=4

f(6)=3(6-2)+4=3(4)+4=12+4=16

Thus, average rate of change will be:

\frac{f(6)-f(2)}{6-2}

⇒ \frac{16-4}{6-2}

⇒ \frac{12}{4}

⇒ 3

Thus, the average rate of change of rainfall in the rainforest between 2nd year and 6th year = 3 inches

8 0
3 years ago
Use the distributive property to solve the equation.<br> 2 (x – 9) = 10
scoundrel [369]

Answer:

x = 14

Step-by-step explanation:

Hi,

To begin, distribute the 2 to the x and -9.

So...

2 ( x - 9 ) = 10

2x - 18 = 10

2x = 28

x = 14

I hope this helps :)

5 0
3 years ago
10<br> 10<br> O A. (3,8)<br> B. (6,5)<br> O c. (5,6)<br> O D. (8,3)
Svetradugi [14.3K]

Answer:

B.(6,5)

Step-by-step explanation:

because (6,5) ang sagot

8 0
3 years ago
Occasionally a savings account may actually pay interest compounded continuously. For each deposit, find the interest earned if
Ugo [173]

1. Occasionally a savings account may actually pay interest compounded continuously. For each​ deposit, find the interest earned if interest is compounded​ (a) semiannually,​ (b) quarterly,​ (c) monthly,​ (d) daily, and​ (e) continuously. Use 1 year = 365 days.

Principal ​$1031

Rate 1.4%

Time 3 years

Answer:

a) $ 44.07

b) $ 44.15

c) $ 44.20

d) $ 44.22

e) $ 44.22

Step-by-step explanation:

The formula to find the total amount earned using compound interest is given as:

A = P(1 + r/n)^nt

Where A = Total amount earned after time t

P = Principal = $1031

r = Interest rate = 1.4%

n = compounding frequency

t = Time in years = 3 years

For each​ deposit, find the interest earned if interest is compounded

(a) semiannually

This means the interest is compounded 2 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/2) ^2 × 3

A = 1031 (1 + 0.007)^6

A = $ 1,075.07

A = P + I where

I = A - P

I = $1075.07 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.07

​(b) quarterly

This means the interest is compounded 4 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/4) ^4 × 3

A = 1031 (1 + 0.014/4)^12

A = $ 1,075.15

I = A - P

I = $1075.15 - $1031

A = P + I where

P (principal) = $ 1,031.00

I (interest) = $ 44.15

(c) monthly,

​ This means the interest is compounded 12 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/12) ^12 × 3

A = 1031 (1 + 0.014/12)^36

A = $ 1,075.20

A = P + I where

I = A - P

I = $1075.20 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.20

(d) daily,Use 1 year = 365 days

This means the interest is compounded 365 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/365) ^2 × 3

A = 1031 (1 + 0.00365)^365 × 3

A = $ 1,075.22

A = P + I where

I = A - P

I = $1075.22 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.22

(e) continuously. .

This means the interest is compounded 2 times in a year

Hence:

A = Pe^rt

A = 1031 × e ^0.014 × 3

A = $ 1,075.22

A = P + I where

I = A - P

I = $1075.22 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.22

5 0
3 years ago
If P-&gt;q is true and q-&gt;r is true them the conclusión of p-&gt;r is also true this is called?​
tino4ka555 [31]

Answer:

This is called transitivity property

4 0
3 years ago
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