Answer:
file_name = 'orders.txt'
file_obj = open( file_name, 'r' )
lines = file_obj.read()
print(lines.upper(), end = '')
Explanation:
- Define the name of the file
.
- Use the built-in open function to open the file in read mode
.
- Use the built-in read function to read the file and assign this to lines variable.
- Finally display the lines by converting them to capital alphabets by using the built-in upper() function.
The complete program is to define a boolean method that returns true if all elements of an array are negative, or return false, if otherwise
The method in java, where comments are used to explain each line is as follows:
//This defines the method
public static boolean chkNegative (double[] myArr) {
//This initializes a boolean variable
boolean isNeg = true;
//This iterates through the array
for (int i = 0; i < myArr.length; i++) {
//If the array element is 0 or positive
if (myArr[i] >= 0) {
//Then the boolean variable is set to false
isNeg = false;
//And the loop is exited
break;
}
}
//This returns true or false
return isNeg;
}
Read more about boolean methods at:
brainly.com/question/18318709
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
A negative externality is when a good costs much greater than what the consumer pays for it. Since you did not provide the possible answers, use this explanation to find the correct answer among the ones you might have.
