On windows, it is the type command.
On linux, the cat command outputs the file.
All bytes that represent printable characters will be displayed as ASCII or even Unicode.
Drones are become more advanced than ever before. Are now, they are starting to impact recreation. They are small, light, and can maneuver incredibly fast. They are being used in movies, skits, short films, and even high-end videos. Here are some ways drones are changing entertainment:
- Providing high-quality filming, even from 200 feet in the air.
- Reaching spaces where bulky helicopters cannot fit into safely
- Laser shows, where drones shine lights and lasers.
Right now, if you tried to hold your phone still to capture a video, you would not be able to do it. Upon checking the footage, you would see the camera shaking, even if it's just tiny bit. While you can lean it on a surface to fix this, it simply cannot be done in the air to capture. Not to worry, though, you've got drones. They can shoot a steady shot 200 feet in the air. The only thing that could rival drones are expensive, bulky choppers. The drones are cheaper and are mass produced.
However, drones are not only being used to filming movies and films. They are also being used for a different kind of entertainment: Shows. Drones move in formation and shine lights in the night sky, like we saw in the Winter Olympics. They are truly stunning(pics attached).
To create a directory, you can use the command mkdir. Below is an example:
mkdir /var/oracle/database/9i
Answer:
#include <iostream>
#include <string>
#include <stack>
#include <math.h>
using namespace std;
int main() {
string s;
double n=0;
int position=0;
stack<int> wholeNumbers;
cout<<"Enter a decimal number:";
cin>>s;
string::iterator counter = s.begin();
while(*counter!='.' && counter!=s.end()){
wholeNumbers.push(*counter-48);
counter++;
position=position+1;
}
for(int i=0;i<position;i++){
n=n+(wholeNumbers.top()*pow(10,i));
wholeNumbers.pop();
}
position=-1;
if(counter!=s.end()){
counter++;
}
while(counter!=s.end()){
n=n+((*counter-48)*pow(10,position));
position=position-1;
counter++;
}
cout<<n;
}
Explanation:
- Inside the while loop, push the push a number to the wholeNumbers stack by subtracting it with 48.
- Increment the counter and position variable by 1 inside the while loop.
- Count the number of digit, push each digit to top of stack and find the end of the number,
- Run a for loop up to the value of position variable and pop a value from the wholeNumbers stack.
Answer:
you highlight it then double tap and click copy or after it is highlighted press ctrl and c together then to paste you double tap and click paste or you can press ctrl v
Explanation: