Answer:
The third quartile is:
Step-by-step explanation:
First organize the data from lowest to highest
4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44
Notice that we have a quantity of n = 20 data
Use the following formula to calculate the third quartile
For a set of n data organized in the form:
The third quartile is :
With n=20
The third quartile is between and
Then
Answer:
(2,-1)
Step-by-step explanation:
A graph is useful here. Points X and Y have coordinate differences of ...
X -Y = (6, 2) -(-2, -4) = (6+2, 2+4) = (8, 6)
Then the distance between X and Y is ...
d = √(8² +6²) = √100 = 10
The point 5 units from X and from Y is the midpoint of XY:
E = (X +Y)/2 = ((6, 2) +(-2, -4))/2 = (4, -2)/2 = (2, -1)
The epicenter is (2, -1).
_____
The graph shows circles of radius 5 around X and Y, and a circle of radius 13 around Z. The circles intersect at the point (2, -1), the epicenter.
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identity
• 1 + cot²x = csc²x
Consider the left side
x -
x
Factorise as a difference of squares
= (csc²x - cot²x)(csc²x + cot²x)
= (1 + cot²x - cot²x)(csc²x + cot²x)
= csc²x + cot²x
= csc²x + csc²x - 1
= 2csc²x - 1 = right side ⇒ verified