The solution to the problem is 16.
first, you must set up the equation.

Then, simplify exponents.
256*
Next, simplify the equation.
16
Find the critical points of
:


All three points lie within
, and
takes on values of

Now check for extrema on the boundary of
. Convert to polar coordinates:

Find the critical points of
:



where
is any integer. There are some redundant critical points, so we'll just consider
, which gives

which gives values of

So altogether,
has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).
<span>A.Two acute angles and two obtuse angles
Hope this helps!
</span>
Step-by-step explanation:
???????? what is easy??
Answer:
12/10 simplified is 1 2/10 or 1 1/5
Step-by-step explanation: