How to factorize this:

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Mathematics

1 answer:

Vinil7 [7]3 years ago

8 0

Ax^2 + bx + c
a = 1
b = -4
c = -5
x^2 -4x-5

-5x1 = -5
-5+1 = -4
(factors of c that also add up to b)

ANSWER: (x-5) (x+1)

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Solve the equation x^6+3x^5+x^4-5x^3-6x^2-2x=0 in the real number system

koban [17]

First, pull out a factor of $x$ .

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Notice that when $x=-1$ (which you can arrive at via the rational root theorem), you have

$(-1)^5+3(-1)^4+(-1)^3-5(-1)^2-6(-1)-2=-1+3-1-5+6-2=0$

which means you can pull out a factor of $x+1$ . Upon dividing you get

$\dfrac{x^5+3x^4+x^3-5x^2-6x-2}{x+1}=x^4+2x^3-x^2-4x-2$

The rational root theorem will come in handy again, suggesting that $x=-1$ appears a second time as a root, which means

$\dfrac{x^4+2x^3-x^2-4x-2}{x+1}=x^3+x^2-2x-2$

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So, you have

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We know that

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VARVARA [1.3K]

Answer:

2. for the first equation, it works, for the second it doesnt so the answer is no

i cant graph for you, but its easy, just use y=mx+b m being the slope which is rise over run

8. x=6, y=-1

10. x=-5 y=5

this is all i could do in such a short notice, but i hope it helped you!

Step-by-step explanation:

for 8, $2x-x+5=11\\x+5=11\\x=6$