Answer:
- 892 lb (right)
- 653 lb (left)
Step-by-step explanation:
The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...
Rcos(45°) +Lcos(75°) = 800
Rsin(45°) -Lsin(75°) = 0
Solving these equations by Cramer's Rule, we get ...
R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))
= 800sin(75°)/sin(120°) ≈ 892 . . . pounds
L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds
The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.
_____
This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...
(right, left) = w/sin(α+β)×(sin(β), sin(α))
Answer:
-10p/3+32-3/2^p
Step-by-step explanation:
Answer:
d = 17.58
Step-by-step explanation:
d = √(x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2
P1(0, 0, 0) P2(8, 7, 14)
Substitute the values in the above equation and you will get
d = √(8 - 0)^2 + (7 - 0)^2 + (14 - 0)^2
= √(64 + 49 + 196)
= √309
= 17.58
; then the area of 
and 
. The surface element is given by
