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mojhsa [17]
3 years ago
9

Which soft skill involves the ability to produce ideas that will give an organization an advantage with respect to other organiz

ations?
A.
conflict resolution
B.
strategic thinking
C.
presentation skills
D.
teamwork
Computers and Technology
1 answer:
KiRa [710]3 years ago
5 0

B.  Strategic thinking

<u>Explanation:</u>

Strategic thinking helps to come up with great ideas that makes the company  better than the other company. One can apply strategic thinking to arrive at decisions that can be related to your work or personal life. Strategic thinking involves developing an entire set of critical skills. Strategic thinking enables a business owner to determine how to use these resources most effectively and advance the company toward its objectives. Strategic thinking focuses the management team on markets that are most likely to succeed.

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You will write a program that reads a binary file that contains records of creatures. Each record can be stored in a Creature st
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Answer:

Explanation:

main.cpp file

/******************************

Name

Date

PA1_Starter.cpp

Description

********************************/

// Headers

#include <iostream>

#include <cstdlib>

#include <string>

#include <vector>

#include <fstream>

#include <algorithm>

using namespace std;

// Global variables

const int CREATURE_NAME_SIZE = 30; // Max length of a creature name

const int CREATURE_TYPE_SIZE = 26; // Max length of a creature type

const string FILENAME = "creatures.dat"; // Name of file that contains the data

// struct used to create records in file

struct Creature

{

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// This function returns true if the name of the left creature is less than the name of the right creature

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bool sortByName(const Creature &lhs, const Creature &rhs)

{

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// Function declarations

// You will need to code the definitions for each of these functions

int getCreatureNumber(int numCreatures);

void displayCreature(fstream& file, int num);

void displaySorted(fstream& file);

int main()

{

char choice; // choice made by user for menu

fstream creatureFile; // file stream for input file

int numCreatures; // the number of creatures saved to the file

 

// Open the creatureFile for input and binary (one statement of code)

 

// Get the number of creatures in the file (two statements of code)

// The number of creatures should be assigned to numCreatures

do

{

cout << "Menu" << endl;

cout << "1. Display a specific creature\n";

cout << "2. Display all creatures sorted by name\n";

cout << "3. Quit\n";

cout << "Enter your choice (1, 2, 3): ";

cin >> choice;

while (cin.get() != '\n');

switch (choice)

{

case '1': // Display a specific creature

displayCreature(creatureFile, getCreatureNumber(numCreatures));

break;

case '2': // Display all the creatures in order

displaySorted(creatureFile);

break;

case '3': // Quit

break;

default:

cout << "Invalid option.\n";

break;

}

if (choice != '3')

{

system("PAUSE");

system("CLS");

}

} while (choice != '3');

creatureFile.close();

 

 

// Make sure we place the end message on a new line

cout << endl;

// The following is system dependent. It will only work on Windows

system("PAUSE");

/*

// A non-system dependent method is below

cout << "Press any key to continue";

cin.get();

*/

return 0;

}

/*******************************************************************

getCreatureNumber gets and returns the record number from the file that the user would like to be displayed

PARAM: numCreatures should be the value of the total number of records (creatures) in the file

PRE: numCreatures contains a value that is equal to the number of records in the file

POST: A value between 1 and numCreatures is returned as selected by the user

NOTE: Do not allow a value less than 1 or greater than numCreatures to be returned

********************************************************************/

int getCreatureNumber(int numCreatures)

{

 

}

/*******************************************************************

displayCreature displays record number num from file

PARAM: file is a fstream that should be open for input and binary

num contains the record number that is to be read in file

PRE: file is a fstream that is open for input and binary

num is a value between 1 and the number of records in file

POST: The record number num is displayed to the monitor

********************************************************************/

void displayCreature(fstream& file, int num)

{

 

}

/*******************************************************************

displaySorted should read file into a vector. It should then sort the vector by

the name of the creature. Last it should display the vector

PARAM: file is a fstream that should be open for input and binary

PRE: file is open for input and binary

POST: Each record is displayed sorted by the name of the creature

********************************************************************/

void displaySorted(fstream& file)

{

 

}

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