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storchak [24]
3 years ago
15

Lucy's savings account has 35% more money than her sister Edy's. Together, the girls have saved a total of $206.80. How much mon

ey has each girl saved?
Mathematics
1 answer:
Ber [7]3 years ago
7 0
X=Lucy´s money
y=Edy´s money
we can suggest this system of equations:
x=y+(35/100)y    ⇒x=135y/100
x+y=206.8

solve by substitution method. 
(135y/100)+y=206.8
Least common multiple=100
135y+100y=20680
235y=20680
y=20680/235=88

then:
x=135y/100=135(88)/100=118.8

Answer:
Lucy´s money=$118.8
Edy´s money=$88

To check:
Together, the girls have   saved a total of $118.8+$88=$206.8
Lucy´s savings account has: $88+(35/100)$88=$118.8, 35% more monty than Edy´s. account.     .                                                                                                                            
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Please help thanks very much
Inga [223]
X/(x+2) = (x+2)/(x+5)
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6 0
3 years ago
Can someone plz help me im really lost
IrinaK [193]
35

12 + 25y = 795

12(y + 20) + 25y = 795

12y + 240 + 25y = 795

37y = 795 - 240

37y= 555

y=15

Substitute y= 15 into

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x= 15 + 20
x= 35

T-shirt = 35
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6 0
3 years ago
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Lauren went to the store an bougth a red hat for $32 and a black hat for $8 how many times as much did the red hat cost as the b
Firlakuza [10]

Answer:

I think 4

Step-by-step explanation:

Red hat costs $32

black hat costs $8

32 (divided) by 8 is 4

3 0
3 years ago
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Simplify the polynomial (4n² + 3n – 5) − (2n² + 3n<br> -<br> + 6)
Veseljchak [2.6K]

Answer:

2n² + 1

Step-by-step explanation:

Given polynomial:

(4n² + 3n – 5) − (2n² + 3n - 6)

Solution:

Removing parentheses,we obtain

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Combine like terms:

  • 4n { }^{2}  - 2n {}^{2}  + 3n - 3n - 5 + 6
  • 2n { }^{2}  + 0 + 1
  • \boxed{2n {}^{2}  + 1}

Done!

Order:BPEMDAS

7 0
2 years ago
this isosceles triangle has two sides of equal length, a, that are longer than the length of the base, b. the perimeter of the t
bezimeni [28]
2 a + b = 15.7
Since the sides are equal length, the equation is:
2 · 6.3 + b = 15.7
We can solve it:
12.6 + b = 15.7
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4 years ago
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