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Hitman42 [59]
3 years ago
14

What the answer now answer only if now answer corry

Mathematics
1 answer:
goblinko [34]3 years ago
6 0

Answer:

Approximately 11.5 units.

Step-by-step explanation:

We need to find the side opposite to ∠W. We are given the two angles ∠W and ∠X. We are also given that Side X is equal to 7. Therefore, we can use the Law of Sines.

Now, like last time, use the Law of Sines:

\frac{\sin(V)}{v}=\frac{\sin(W)}{w}=\frac{\sin(X)}{x}

We can ignore the first term. Plug in 144 for ∠W, 21 for ∠X, and 7 for <em>x</em>.

\frac{\sin(144)}{w}=\frac{\sin(21)}{7}

Cross multiply:

7\sin(144)=w\sin(21)\\w=\frac{7\sin(144)}{\sin(21)} \\v\approx11.4812\approx11.5

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Step 1:

first let us convert the two decimals into fractions.

0.36=36/100 (since there are two digits after decimal point we divide by 100)

2.4=24/10 (since there are one digit after decimal point we divide by 10)

now we can multiply the fractions

\frac{36}{100}×\frac{24}{10}

multiplying numerator with numerator and denominator with denominator:

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=\frac{864}{1000}

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7 0
3 years ago
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7.7.33
GenaCL600 [577]
We know that

At sea level, the height is 0 and
the pressure is 98 kilopascals

At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%

</span>i(100%-11.41%)/100----> (0.8859)

therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals


the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
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3 years ago
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