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nadezda [96]
3 years ago
15

How do I find the product when multiplying with decimals

ula1" title="0.36 \times 2.4" alt="0.36 \times 2.4" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
stellarik [79]3 years ago
7 0

Step 1:

first let us convert the two decimals into fractions.

0.36=36/100 (since there are two digits after decimal point we divide by 100)

2.4=24/10 (since there are one digit after decimal point we divide by 10)

now we can multiply the fractions

\frac{36}{100}×\frac{24}{10}

multiplying numerator with numerator and denominator with denominator:

\frac{36*24}{100*10}

=\frac{864}{1000}

Now we can convert this back to decimal

864/1000=0.864, moving decimal three digits to the left since we have three zeros in the denominator that is 1000.

Answer=0.864

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natta225 [31]

Answer:

11/14

Step-by-step explanation:

11/4 / 3 1/2

3 1/2= 3*2+1= 6+1=7/2

11/4 * 2/7= 22/28

22/2=11

28/2= 14

11/14

4 0
3 years ago
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Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

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o-na [289]

Answer:

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