Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
Answer:
w=12 or w=2
Step-by-step explanation:
2w^2-16w=12w-48
2w^2-28w=-48
2w^2-28w+48=0
2(w^2-14w+24)=0
2(w-12)(w-2)=0
(w-12)(w-2)=0
w=12 or w=2
Hmmmm well I would first round the 1 and make it a 0 round the 9 and add to 6 and round 7 (was originally 6) to add 1 to 25 and then round 26 to 30
Answer:
10+10
Step-by-step explanation:
Answer:
-57
Step-by-step explanation:
13,8,3,-2 (decreasing by 5)
13,8,3,-2,-7,-12,-17,-22,-27,-32,-37,-42,-47,-52,-57.
The 15th term is -57.
<u><em>Ace</em></u>
