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2 years ago

3s+2t−3 =c −7s−5t =4

Mathematics

1 answer:

irinina [24]2 years ago

3 0

Answer:

−4

s−t+

−4

Step-by-step explanation:

Let's solve for c.

3s+2t−3c−7s−5t=4

Step 1: Add 4s to both sides.

−3c−4s−3t+4s=4+4s

−3c−3t=4s+4

Step 2: Add 3t to both sides.

−3c−3t+3t=4s+4+3t

−3c=4s+3t+4

Step 3: Divide both sides by -3.

−3c

−3

4s+3t+4

−3

−4

s−t+

−4

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1. 4 $x^{3}$ + 26x² + 4x - 48

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Vlad [161]

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b. $v(t)$ gives the Johanna's velocity at time $t$ . The magnitude of her velocity, or speed, is $|v(t)|$ . Integrating this would tell us the total distance she has traveled whilst jogging.

The Riemann sum approximates the integral as

$\displaystyle\int_0^{40}|v(t)|\,\mathrm dt=12\cdot200+8\cdot240+4\cdot220+16\cdot150=7600$

If you're not sure how this is derived: we're given 5 sample points, so we can cut the interval [0, 40] into 4 subintervals. The lengths of each subinterval are 12, 8, 4, and 16 (the distances between each sample point), and the height of the rectangle approximating the area under the plot of $|v(t)|$ is determined by the value of $v(t)$ at each sample point, 200, 240, |-220| = 220, and 150.

c. Bob's velocity is given by $B(t)$ , so his acceleration is given by $B'(t)$ . We have