Can someone help me on this one pls

Mathematics

1 answer:

Natali [406]3 years ago

6 0

Answer:

The dimensions of the rectangle would be a Length of 7 units and a Height of 6 units, or C. 6 units and D. 7 units

Step-by-step explanation:

The <u>dimensions</u> of the rectangle are found by calculating the distance between various corner points. (We can find the distance between any two points if we know their coordinates. So in the figure (of your question):

HEIGHT - of the rectangle is the distance between A and B ( or C,D). The formula for the distance between two points, is (square root) of dx squared (distance in x-coordinates of A,B ) + dy squared (distance in y-coordinates of A,B)

AB = $\sqrt{7.2x^{2}+0.2y^{2} }$ = 7.2

WIDTH - is the distance between B and C (or A,D). The formula for the distance between two points, is (square root) of dx squared (distance in x-coordinates of B,C) + dy squared (distance in y-coordinates of B,C)

BC = $\sqrt{0.6x^{2} +6.3y^{2} }$ = 6.3

LENGTH of a DIAGONALS is the distance between opposite corners, say B and D (or A,C since the diagonals are congruent).

BD = $\sqrt{7.1x^{2} + 6.3y^{2} }$ = 9.5

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If g(x)=4x^2-16 we’re shifted 9 united to the right and 1 down, what would the new equation be?

Inessa05 [86]

Shown in the graph

<h2>Explanation:</h2>

Using graph tools we can graph the function:

$g(x)=4x^2-16$

which is the red graph shown below. As you can see, this is a parabola. The rule for vertical and horizontal shifts is as follows:

$Let \ c \ be \ a \ positive \ real \ number. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:$

$\bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ h(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ h(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ right \ \mathbf{right}: \\ h(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ left \ \mathbf{left}: \\ h(x)=f(x+c)$