9514 1404 393
Answer:
Step-by-step explanation:
Let g and b represent the numbers of candy canes the girl and boy have, respectively.
g -1 = b +1 . . . . . . girl gives to boy, they're equal
g +1 = 2(b -1) . . . . boy gives to girl; she has double
Adding 1 to the first equation gives an expression for g that can be substituted into the second equation.
g = b +2
(b +2) +1 = 2b -2
5 = b . . . . . . . . . . add 2-b, simplify
g = 5+2 = 7 . . . . . find g
The girl has 7 candy canes; the boy has 5.
Answer: I acculy hate when ppl think they can spam report all the questions ppl have nut when ppl do it to them they mad so just do it back see how they feel to be reported in all of there questions
Step-by-step explanation:
Beats me man not enough information
Answer:
15 cm ft²
Step-by-step explanation:
need ko po that are many means
Answer:
The Nyquist sampling theorem states that the sampling frequency must be at least twice of the highest frequency component present in the signal.
Mathematically,
Samling rate ≥ 2×fmax
Step-by-step explanation:
We know that sound is an analog signal comprising of several different frequencies. We convert this analog signal into a digital signal by means of an analog-to-digital converter (ADC) for the purpose of storage and transmission.
For accurate and faithful analog to digital conversion, we need to take some samples per second which is basically called "Sampling rate".
So how many samples do we need?
This is where Nyquist sampling theorem comes into the picture.
Nyquist Sampling theorem:
The Nyquist sampling theorem states that the sampling rate must be at least twice of the highest frequency component present in the signal.
Mathematically,
Samling rate ≥ 2×fmax
This is the minimum sampling frequency that is required to avoid distortion of the signal.
If the Nyquist criteria is not followed then some of the information in the analog signal will be lost and the sound will not be accurately converted into the digital signal.
Therefore, a higher sampling rate would result in better reproduction of sound as compared to a lower sampling rate.
On the other hand, a higher sampling rate would also take more storage memory and reduced transmission speed.
