To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
7 multiply by three u get 21 then add it to the number 28 add u get the answer 49
Answer:
okay look at it this way:
Step-by-step explanation:
when you use a mirror and you look at the shape on both sides then you will see the -x which is basically on the same side but just a minus instead. Soo let's say you have to graph a coordinate of (2,4) y=2 and x=4 si you have to graph the normal plots and when you put it in the opposite sides the thing you only did was you just made a reflection of the shape just negative instead. hope you understand what I'm saying.
(reflective)
Total expenses;
1/2*60=30
2/3*30=20
Total = 50
Remainder;
60-50
<span>£</span>10
