Suppose you add x liters of pure water to the 10 L of 25% acid solution. The new solution's volume is x + 10 L. Each L of pure water contributes no acid, while the starting solution contains 2.5 L of acid. So in the new solution, you end up with a concentration of (2.5 L)/(x + 10 L), and you want this concentration to be 10%. So we have
and so you would need to add 15 L of pure water to get the desired concentration of acid.
Answer:
y < 5
Step-by-step explanation:
Given
y + 1 < 6 ( isolate y on the left side by subtracting 1 from both sides )
y < 5
Answer:
3 √5
Step-by-step explanation:
7 words per minute! :) Hope I helped!!
Month_1 Value = Month_0 Value * 0.95
Month_2 Value = Month_1 Value * 0.95 = Moth_0 Value * 0.95*0.95 = Month_0 Value * 0.95^2
Month _n Value = Month_0 Value * (0.95)^n
After 2 years ==> n = 24
Month_24 Value = Month_0 Value * (0.95)^24 = 2,000,000 *(0.95)^24 = 583,978.05
