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mihalych1998 [28]
3 years ago
15

Solve for x. 7(1x - 3) = 4(x + 5)

Mathematics
1 answer:
alexandr1967 [171]3 years ago
6 0

Answer:

x = 41/3

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

7(1x - 3) = 4(x + 5)

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Simplify:                                        7(x - 3) = 4(x + 5)
  2. Distribute:                                     7x - 21 = 4x + 20
  3. Subtract 4x on both sides:          3x - 21 = 20
  4. Add 21 on both sides:                  3x = 41
  5. Divide 3 on both sides:                x = 41/3

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution.</em>

  1. Substitute:                    7(1(41/3) - 3) = 4(41/3 + 5)
  2. Multiply:                        7(41/3 - 3) = 4(41/3 + 5)
  3. Subtract/Add:               7(32/3) = 4(56/3)
  4. Multiply:                        224/3 = 224/3

Here, we see that 224/3 is indeed equivalent to 224/3. ∴ x = 41/3 is a solution to the equation.

And we have our final answer!

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Answer:

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Step-by-step explanation:

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The backyard is 20 inches long and 37 inches wide. What is the area of the backyard.
gizmo_the_mogwai [7]

            - - - - - - -- - - - - - - - - - - - - -- -

\diamond\large\textsf{\textbf{\underline{Given\:question:-}}}

          The backyard is 20 inches long and 37 inches wide. What is the area of the backyard?

\diamond\large\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}

We are given the backyard's length (20 inches long) and the backyard's width (37 inches wide).

We are asked to find the area of the backyard, which can be found using the following formula:-

      \boxed{\bold{A_{(rectangle)}=LW}}

<u>Where:-</u>

<u></u>

  • A=Area of rectangle
  • L=Length (20 inches)
  • W=Width (37 inches)

Substitute the values:-

\boxed{\bold{A=20*37}}

On simplification,

✳︎ \boxed{\bold{A=740\:in^2}}, which is our final answer.

<h3> Good luck with your studies.</h3>

        - - - - - - - - - - -- - - - - - - - - - - - - - - - - - - - - -

5 0
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5 0
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