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Mariana [72]
3 years ago
13

George Orwell based his novel, 1984, on the idea of

Mathematics
1 answer:
ehidna [41]3 years ago
3 0
The correct answer is


<span>totalitarianism</span>
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Amy needs to mix 5 cups of baking soda with 6 cups of water to make a cleaning solution. How many cups of baking soda are needed
Ivenika [448]
5 cups of soda ------- 6 cups of  water
x cups of soda -------- 1 cup of water

x= 5*1/6 = 5/6

Answer : <span>B.5/6</span>
4 0
3 years ago
Read 2 more answers
Darnelle has a $10,000, three-year loan with an APR of 5%. She uses the table on page 159 to compute information on the loan,
Leno4ka [110]

Answer:

a:500 b:547,500 c:557,500

Step-by-step explanation:

7 0
3 years ago
For every batch of cookies Carla's made , her brother ate 2 cookies. If Carla's brother ate a total of 6 cookies, how many batch
spayn [35]

Step-by-step explanation:

number of the total cookies ÷ the nber her brother ate

6÷2=3

3 0
3 years ago
Multiply.<br>(2x-5) (3x-7)​
Naya [18.7K]

Answer:

6x^2 -29 +35.

Step-by-step explanation:

use the FOIL method(First, Outer,Inner, and Last.)

2x x 3x=6x^2.

2x x -7=-14x.

-5 x 3x =-15x.

-5 x -7=35.

= 6x^2 -14x -15x+35

6x^2 -29x +35.

4 0
3 years ago
At a large Midwestern university, a simple random sample of 100 entering freshmen in 1993 found that 20 of the sampled freshmen
guajiro [1.7K]

Answer:

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

p1 -> 1993

20 out of 100, so:

p_1 = \frac{20}{100} = 0.2

s_1 = \sqrt{\frac{0.2*0.8}{100}} = 0.04

p2 -> 1997

10 out of 100, so:

p_2 = \frac{10}{100} = 0.1

s_2 = \sqrt{\frac{0.1*0.9}{100}} = 0.03

Distribution of p1 – p2:

p = p_1 - p_2 = 0.2 - 0.1 = 0.1

s = \sqrt{s_1^2+s_2^2} = \sqrt{0.04^2 + 0.03^2} = 0.05

Confidence interval:

p \pm zs

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.  

The lower bound of the interval is:

p - zs = 0.1 - 1.645*0.05 = 0.01775&#10;

The upper bound of the interval is:

p + zs = 0.1 + 1.645*0.05 = 0.18225&#10;

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

6 0
3 years ago
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