Answer:
A correlation exists in a scatter plot if there is a general trend in the outputs as inputs increase. If the outputs generally increase in value, then there is a positive correlation. If the outputs generally decrease in value, then there is a negative correlation.
Answer:
Step-by-step explanation:
y=(2x²+x)³+(x-1)/(1-x)
=(2x²+x)³+(x-1)/-(x-1)
=(2x²+x)³-1
dy/dx=3(2x²+x)(4x+1)-0
=3x(2x+1)(4x+1)
Answer:
f(1) ≈ 2.7864
Step-by-step explanation:
You appear to want a couple of iterations of ...
... y[n+1] = y[n] +arcsin(x[n]·y[n]}·(x[n+1] -x[n])
... x[n+1] = x[n] +0.5
... x[0] = 0
... y[0] = 2
Filling in the values, we get
... y[1] = 2 + arcsin(0·2)·0.5 = 2
... y[2] = 2 + arcsin(0.5·2)·0.5 = 2 +(π/2)·0.5 ≈ 2.7864 . . . . corresponds to x=1
Answer:
(3,2)
Step-by-step explanation:
the other three ordered pairs do not lie in the shaded region