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Leto [7]
3 years ago
13

Is the confidence interval equivalent to the expression is it equivalent to the expression?

Mathematics
1 answer:
Akimi4 [234]3 years ago
4 0
<span>Two or more expressions (equations are examples) that are equal to or equivalent to each other; for example: (X+2)(X+4) = X^2+6X+8.</span>
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Find the value of x.
vredina [299]

Answer:

50

Step-by-step explanation:

8 0
3 years ago
Find the values of x and y that make these triangles congruent by the HL Theorem.
RideAnS [48]

According to HL theorem if one leg and hypotenuse of one right triangle are equal to one leg and hypotenuse of other right triangle, then the triangles are congruent.

By using this theorem we can set up the system of equations as follows:

x=y+1 ...(1)

2x+3= 3y + 3 ..(2)

By using equation (1) next step is to plug in y+1 for x in equation (2). So,

2 ( y + 1) + 3 = 3y + 3

2y + 2 + 3 = 3y + 3 By using distribution property.

2y + 5 = 3y + 3

2y + 5 - 5 = 3y + 3 - 5 Subtract 5 from each side.

2y = 3y - 2

2y - 3y = -2 Subtract 3y from each sides.

-y = -2

So, y=2

Next step is to plug in y=2 in equation (1) to get the value of x. Hence,

x= 2+1

=3

So, x=3 and y=2 make these triangles congruent.

So, the correct choice is 3. x = 3, y = 2.

7 0
2 years ago
Allyson works at Designer Tattoos. Her regular hourly wage is $22.20. If she regularly works 34 hours per week, what is her regu
ExtremeBDS [4]

Answer:

754.80

Step-by-step explanation:

22.20*34=754.80

6 0
2 years ago
Read 2 more answers
A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought i
garri49 [273]

Answer:

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

System of hypothesis

We want to test if the true mean is higher than 5, the system of hypothesis are :  

Null hypothesis:\mu \leq 5  

Alternative hypothesis:\mu > 5  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

6 0
3 years ago
a worker A finishes a project on his own in 12 days. the worker completes the same work alone in 16 days. the two workers starte
ankoles [38]

Answer:

<em>Worker B needs 9 days to finish the rest of the work</em>

Step-by-step explanation:

<u>Proportions</u>

Worker A finishes a project on his own in 12 days and worker B does the same in 16 days.

Worker A does 1/12 of the project in one day and worker B does 1/16 of the project in one day. When working together, they do

\frac{1}{12}+\frac{1}{16}=\frac{7}{48}

After 3 days they have completed:

3*\frac{7}{48}=\frac{7}{16}

parts of the project, this means it still remains:

1-\frac{7}{16}=\frac{9}{16}

parts of the project and it is done by B alone. Since B does \frac{1}{16} per day, he now takes

\displaystyle \frac{\frac{9}{16}}{\frac{1}{16}}=9

days to complete the project.

Worker B needs 9 days to finish the rest of the work

4 0
3 years ago
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