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Likurg_2 [28]
3 years ago
12

Cavalieri’s principle states that two solids with equal heights and cross sectional volumes at every level have equal areas

Mathematics
2 answers:
zaharov [31]3 years ago
7 0

Answer:

False

Step-by-step explanation:

We are given a statement regarding Cavalieri's principle.

The given statement is false.

CavalierIi's principle.

  • Two solids of equal altitude or height, the cross-sections made by planes parallel to the base of the solid are always equal, then the volumes of the two solids are said to be equal.
  • If two solids or 3-D figures are considered between two parallel planes. If the cross sectional area formed by the intersection of the planes and the solid figure are equal, then the two solids have equal volumes.
  • The given equation states the equality of cross sectional area in place of the volume.
  • Thus, the given statement is false.

svetlana [45]3 years ago
5 0

Answer:

False

Step-by-step explanation:

we know that

The <u><em>Cavalieri's principle</em></u> states that if two or more figures have the same cross-sectional area at every level and the same height, then the figures have the same volume.

see the attached figure to better understand the problem

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2 AND 4

Step-by-step explanation:

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3 years ago
ABCD and EFGH are squares. If JH= 4cm and JC=9cm, then what is the area of the shaded region?
romanna [79]
The squares are shown in the attached picture.

As you can see, JC is half the diagonal of ABCD and JH is half the diagonal of EFGH.

In order to find the area of the shaded figure, we need to subtract the area of the white square (EFGH) from the area of the big square (ABCD).

The area of a square know the diagonal is given by the formula:
A = d² ÷ 2

A(ABCD) = (2×JC)² ÷ 2
                = (2×9)² ÷ 2
                = 162 cm²

A(EFGH) = (2×JH)² ÷ 2
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Therefore:
A = A(ABCD) - <span>A(EFGH)
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The area of the shaded region is 130 cm².

3 0
3 years ago
What’s the distance between (3,4) , (7,2)
Reptile [31]

Answer:

D= 4.47

Step-by-step explanation:

Here we are given with two coordinates and asked to determine the distance between them.

Here we are going to use the distance formula, which is given as under

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

 

Where

(x_1,y_1) = (3,4)

(x_2,y_2) = (7,2)

 

Replacing these values in the distance formula

D =\sqrt{(7-3))^2+(2-4)^2}

D =\sqrt{(4)^2+(-2)^2}

D =\sqrt{16+4}

D =\sqrt{20}

D= 4.47

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4 years ago
X + 3y = 12 2 x - 4 y = 4solve by graphing.
zloy xaker [14]
\begin{gathered} x+3y=12 \\ 2x-4y=4 \end{gathered}\begin{gathered} x=12-3y \\  \\ 2(12-3y)-4y=4 \\ 24-6y-4y=4 \\ 24-10y=4 \\ -10y=-20 \\ y=2 \\  \\ x=12-3(2) \\ x=12-6 \\ x=6 \end{gathered}

By graphing

4 0
1 year ago
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