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Anastasy [175]
3 years ago
10

If dh = 3x -3 and fh = x+7, find the value of x for which defg must be a parallelogram.

Mathematics
2 answers:
rosijanka [135]3 years ago
4 0

Answer:

Option c is correct

x = 5

Step-by-step explanation:

Properties of parallelogram:

  • Opposites sides are congruent.
  • Opposites angle are congruent
  • Diagonal of parallelogram bisect each other.

As per the statement:

In the given DEFG parallelogram,

DH = 3x-3 units

FH=x+7 units

by properties of parallelogram we have;

DH = FH

3x-3 = x+7

Subtract x from both sides we have;

2x-3 =7

Add 3 to both sides we have;

2x=10

Divide both sides by 2 we have;

x = 5

Therefore, the value of x for which DEFG must be a parallelogram is, 5

Ugo [173]3 years ago
3 0
<span>parallelogram
DH = FH
</span><span>3x -3 = x + 7
</span>2x = 10
  x = 5

Answer
<span>c. 5</span>
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