Question

If dh = 3x -3 and fh = x+7, find the value of x for which defg must be a parallelogram.

Answer 1

Answer:

Option c is correct

x = 5

Step-by-step explanation:

Properties of parallelogram:

• Opposites sides are congruent.

• Opposites angle are congruent

• Diagonal of parallelogram bisect each other.

As per the statement:

In the given DEFG parallelogram,

DH = 3x-3 units

FH=x+7 units

by properties of parallelogram we have;

DH = FH

$3x-3 = x+7$

Subtract x from both sides we have;

$2x-3 =7$

Add 3 to both sides we have;

$2x=10$

Divide both sides by 2 we have;

x = 5

Therefore, the value of x for which DEFG must be a parallelogram is, 5

Answer 2

parallelogram
DH = FH
3x -3 = x + 7
2x = 10
  x = 5

Answer
c. 5